1
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason $\mathbf{R}$

Statement I : Change in internal energy of a system containing $n$ mole of ideal gas can be written as $\Delta \mathrm{U}=n \mathrm{C}_v\left(T_{\mathrm{f}}-T_i\right)=\frac{n R}{\gamma-1}\left(T_{\mathrm{f}}-T_i\right)$, where $\gamma=\frac{C_p}{C_v}, T_i=$ initial temperature, $T_{\mathrm{f}}=$ final temperature.

Statement II : Relation between degree of freedom $f$ and $\gamma\left(=C_p / C_v\right)$ is $\left(\gamma=1+\frac{2}{f}\right)$

Choose the correct answer from the options given below

A

Both $\mathbf{A}$ and $\mathbf{R}$ are true and $\mathbf{R}$ is the correct explanation of $\mathbf{A}$

B

Both $\mathbf{A}$ and $\mathbf{R}$ are true but $\mathbf{R}$ is NOT the correct explanation of $\mathbf{A}$

C

A is true but $\mathbf{R}$ is false

D

A is false but $\mathbf{R}$ is true

2
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider the following statements:

A. Zeroth law of thermodynamics gives concept of temperature

B. First law of thermodynamics gives concept of internal energy

C. In isothermal expansion of ideal gas, $\Delta Q \neq \Delta W$

D. Product of intensive and extensive variables is extensive

E. The ratio of any extensive variable to mass will be an extensive variable

Choose the correct combination of statements from the options given below:

A

C, D and E Only

B

A, B and C Only

C

A, B and D Only

D

B, C and D Only

3
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Refer to the figure given below. The values of $I_1, I_2$ and $I_3$ are $\_\_\_\_$ .

JEE Main 2026 (Online) 5th April Morning Shift Physics - Current Electricity Question 2 English
A

$I_1=2.5 \mathrm{~A}, I_2=1.875 \mathrm{~A}, I_3=1.875 \mathrm{~A}$

B
$I_1=1.875 \mathrm{~A}, I_2=2.5 \mathrm{~A}, I_3=1.875 \mathrm{~A}$
C
$I_1=1.875 \mathrm{~A}, I_2=1.875 \mathrm{~A}, I_3=2.5 \mathrm{~A}$

D

$I_1=2.5 \mathrm{~A}, I_2=2.5 \mathrm{~A}, I_3=1.875 \mathrm{~A}$

4
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An electron of mass $m$ is moving in an electric field $\vec{E}=-2 E_{\mathrm{o}} \hat{i}\left(E_{\mathrm{o}}=\right.$ constant $\left.>0\right)$, with an initial velocity $\vec{V}=v_{\mathrm{o}} \hat{i} \left(v_{\mathrm{o}}=\right.$ constant $\left.>0\right)$. If $\lambda_{\mathrm{o}}=\frac{h}{4 m v_{\mathrm{o}}}$, its de Broglie wavelength at time $t$ is

$\_\_\_\_$ .

( $e=$ charge of electron)

A

$$ \frac{4 \lambda_{\mathrm{o}}}{\left[1-\frac{E_{\mathrm{o}} e}{2 m} \frac{t}{v_{\mathrm{o}}}\right]} $$

B

$$ \frac{4 \lambda_{\mathrm{o}}}{\left[1+\frac{E_{\mathrm{o}} e}{2 m} \frac{t}{v_{\mathrm{o}}}\right]} $$

C

$$ \frac{4 \lambda_{\mathrm{o}}}{\left[1+\frac{2 E_{\mathrm{o}} e}{m} \frac{t}{v_{\mathrm{o}}}\right]} $$

D

$$ \frac{4 \lambda_{\mathrm{o}}}{\left[1-\frac{2 E_{\mathrm{o}} e}{m} \frac{t}{v_{\mathrm{o}}}\right]} $$

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