1
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements :

Statement I : On the basis of inductive effect, the order of stability of alkyl carbanions is $\mathrm{CH}_3{ }^{-}>\mathrm{CH}_3-\mathrm{CH}_2{ }^{-}>\left(\mathrm{CH}_3\right)_2 \mathrm{CH}^{-}>\left(\mathrm{CH}_3\right)_3 \mathrm{C}^{-}$.

Statement II : Allyl and benzyl carbanions are more stabilised by inductive effect and not by resonance effect.

In the light of the above statements, choose the correct answer from the options given below :

A

Both Statement I and Statement II are correct

B

Both Statement I and Statement II are incorrect

C

Statement I is correct but Statement II is incorrect

D

Statement I is incorrect but Statement II is correct

2
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

For the following Friedel Craft's alkylation reaction, which of the statements are correct?

JEE Main 2026 (Online) 5th April Morning Shift Chemistry - Hydrocarbons Question 5 English

A. Major product is n-propyl benzene.

B. iso-propyl carbocation intermediate is also generated.

C. Multiple substitution is inevitable.

D. Introducing electron-donating substituent on benzene will not produce any alkyl benzene.

Choose the correct answer from the options given below :

A

A and D only

B

B and C only

C

A and C only

D

B and D only

3
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

$$ \text {Benzyl isocyanide can be obtained from } $$

JEE Main 2026 (Online) 5th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 2 English

Choose the correct answer from the options given below :

A

A and B Only

B

A and C Only

C

B and D Only

D

D and E Only

4
JEE Main 2026 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider compounds $\mathrm{A}, \mathrm{B}$ and C with following structural formulae

$$ \begin{aligned} & \mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH} \\ & \mathrm{~B}=\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3 \\ & \mathrm{C}=\mathrm{HO}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}(\mathrm{OH})-\mathrm{CH}_3 \end{aligned} $$

For the conversion of B from A , reagent (D) required is $\_\_\_\_$ and structural formula of product $(\mathrm{E})$ obtained when C undergoes same reaction using excess reagent (D) is $\_\_\_\_$ .

A

$$ \begin{array}{|c|c|} \hline \text { D } & \text { E } \\ \hline \text { Conc. } \mathrm{H}_2 \mathrm{SO}_4 & \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}(\mathrm{OH}) \mathrm{CH}_3 \\ \hline \end{array} $$

B

$$ \begin{array}{|c|c|} \hline \mathrm{D} & \mathrm{E} \\ \hline \mathrm{PCC} & \mathrm{HO}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2 \\ \hline \end{array} $$

C

$$ \begin{array}{|c|c|} \hline \text { D } & \text { E } \\ \hline \text { PCC } & \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2 \\ \hline \end{array} $$

D

$$ \begin{array}{|c|c|} \hline \text { D } & \mathrm{E} \\ \hline \text { Conc. } \mathrm{H}_2 \mathrm{SO}_4 \text { or } \mathrm{H}_3 \mathrm{PO}_4 & \mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2 \\ \hline \end{array} $$

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