1
JEE Main 2026 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The heat of atomisation of methane and ethane are ' x ' $\mathrm{kJ} \mathrm{mol}^{-1}$ and ' y ' $\mathrm{kJ} \mathrm{mol}^{-1}$ respectively. The longest wavelength ( $\lambda$ ) of light capable of breaking the $\mathrm{C}-\mathrm{C}$ bond can be expressed in SI unit as :

A

$\frac{\mathrm{N}_{\mathrm{A}} \mathrm{hc}}{250(y-6 x)}$

B

$\mathrm{N}_{\mathrm{A}} \mathrm{hc}\left(y-\frac{6 x}{4}\right)^{-1}$

C

$\frac{\mathrm{hc}}{1000}\left(\frac{y-6 x}{4}\right)^{-1}$

D

$\frac{\mathrm{N}_{\mathrm{A}} \mathrm{hc}}{250(4 y-6 x)}$

2
JEE Main 2026 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Pair of species among the following having same bond order as well as paramagnetic character will be-

A

$\mathrm{O}_2^{-}, \mathrm{N}_2^{+}$

B

$\mathrm{O}_2{ }^{+}, \mathrm{N}_2{ }^{2-}$

C

$\mathrm{O}_2^{-}, \mathrm{N}_2^{-}$

D

$\mathrm{O}_2^{+}, \mathrm{N}_2^{-}$

3
JEE Main 2026 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The unsaturated ether on acidic hydrolysis produces carbonyl compounds as shown below :-

JEE Main 2026 (Online) 24th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 16 English 1

Based on this, predict the solution/reagent that will help to distinguish "P" and "Q" obtained in the following reaction :-

JEE Main 2026 (Online) 24th January Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 16 English 2
A

Saturated $\mathrm{NaHSO}_3$ solution

B

Fehling solution

C

Lucas reagent

D

2, 4 - DNP reagent

4
JEE Main 2026 (Online) 24th January Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Consider the following gaseous equilibrium in a closed container of volume ' $V$ ' at $\mathrm{T}(\mathrm{K})$.

$$ \mathrm{P}_2(\mathrm{~g})+\mathrm{Q}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{PQ}(\mathrm{~g}) $$

2 moles each of $\mathrm{P}_2(\mathrm{~g}), \mathrm{Q}_2(\mathrm{~g})$ and $\mathrm{PQ}(\mathrm{g})$ are present at equilibrium. Now one mole each of ' $\mathrm{P}_2$ ' and ' $\mathrm{Q}_2$ ' are added to the equilibrium keeping the temperature at $\mathrm{T}(\mathrm{K})$. The number of moles of $\mathrm{P}_2, \mathrm{Q}_2$ and PQ at the new equilibrium, respectively, are

A

$2.56,1.62,2.24$

B

$2.67,2.67,2.67$

C

1.21, 2.24, 1.56

D

$1.66,1.66,1.66$

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