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JEE Main 2026 (Online) 23rd January Morning Shift
Numerical
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-1
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The crystal field splitting energy of $\left[\mathrm{Co}(\text { oxalate })_3\right]^{3-}$ complex is ' $n^{\prime}$ times that of the $\left[\mathrm{Cr}(\text { oxalate })_3\right]^{3-}$ complex. Here ' $n$ ' is $\_\_\_\_$ . (Assume $\Delta_0 \gg P$ )

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2
JEE Main 2026 (Online) 23rd January Morning Shift
Numerical
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For the following gas phase equilibrium reaction at constant temperature,

$$ \mathrm{NH}_3(\mathrm{~g}) \rightleftharpoons 1 / 2 \mathrm{~N}_2(\mathrm{~g})+3 / 2 \mathrm{H}_2(\mathrm{~g}) $$

if the total pressure is $\sqrt{3} \mathrm{~atm}$ and the pressure equilibrium constant $\left(K_p\right)$ is 9 atm , then the degree of dissociation is given as $\left(x \times 10^{-2}\right)^{-1 / 2}$. The value of $x$ is $\_\_\_\_$ . (nearest integer)

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3
JEE Main 2026 (Online) 23rd January Morning Shift
Numerical
+4
-1
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For the thermal decomposition of reactant $\mathrm{AB}(\mathrm{g})$, the following plot is constructed.

JEE Main 2026 (Online) 23rd January Morning Shift Chemistry - Chemical Kinetics and Nuclear Chemistry Question 19 English

The half life of the reaction is ' $x^{\prime} \,\mathrm{min}$.

$x=$ $\_\_\_\_$ min. (Nearest integer)

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4
JEE Main 2026 (Online) 23rd January Morning Shift
Numerical
+4
-1
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$x $ $\mathrm{mg}$ of pure HCl was used to make an aqueous solution. 25.0 mL of $0.1 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_2$ solution is used when the HCl solution was titrated against it. The numerical value of $x$ is $\_\_\_\_$ $\times 10^{-1}$. (Nearest integer)

Given : Molar mass of HCl and $\mathrm{Ba}(\mathrm{OH})_2$ are 36.5 and $171.0 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively.

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