It is noticed that $\mathrm{Pb}^{2+}$ is more stable than $\mathrm{Pb}^{4+}$ but $\mathrm{Sn}^{2+}$ is less stable than $\mathrm{Sn}^{4+}$. Observe the following reactions.

$$ \begin{aligned} & \mathrm{PbO}_2+\mathrm{Pb} \rightarrow 2 \mathrm{PbO} ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(1) \\ & \mathrm{SnO}_2+\mathrm{Sn} \rightarrow 2 \mathrm{SnO} ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(2) \end{aligned} $$

Identify the correct set from the following

Identify the CORRECT set of details from the following :

A. $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ : Inner orbital complex; $\mathrm{d}^2 \mathrm{sp}^3$ hybridized

B. $\left[\mathrm{MnCl}_6\right]^{3-}$ : Outer orbital complex; $\mathrm{sp}^3 \mathrm{~d}^2$ hybridized

C. $\left[\mathrm{CoF}_6\right]^{3-}$ : Outer orbital complex; $\mathrm{d}^2 \mathrm{sp}^3$ hybridized

D. $\left[\mathrm{FeF}_6\right]^{3-}$ : Outer orbital complex; $\mathrm{sp}^3 \mathrm{~d}^2$ hybridized

E. $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ : Inner orbital complex; $\mathrm{sp}^3$ hybridized

Choose the correct answer from the options given below :

Elements X and Y belong to Group 15. The difference between the electronegativity values of ' X ' and phosphorus is higher than that of the difference between phosphorus and ' Y '. ' X ' & ' Y ' are respectively

Consider the following reaction of benzene.

In compound $(Q)$, the percentage of oxygen is $\_\_\_\_$ %. (Nearest integer)