1
JEE Main 2020 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let [t] denote the greatest integer $$ \le $$ t and $$\mathop {\lim }\limits_{x \to 0} x\left[ {{4 \over x}} \right] = A$$.
Then the function, f(x) = [x2]sin($$\pi $$x) is discontinuous, when x is equal to :
A
$$\sqrt {A + 1} $$
B
$$\sqrt {A + 5} $$
C
$$\sqrt {A + 21} $$
D
$$\sqrt {A} $$
2
JEE Main 2020 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If $$x = 2\sin \theta - \sin 2\theta $$ and $$y = 2\cos \theta - \cos 2\theta $$,
$$\theta \in \left[ {0,2\pi } \right]$$, then $${{{d^2}y} \over {d{x^2}}}$$ at $$\theta $$ = $$\pi $$ is :
A
$${3 \over 8}$$
B
$${3 \over 2}$$
C
$${3 \over 4}$$
D
-$${3 \over 4}$$
3
JEE Main 2020 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The length of the minor axis (along y-axis) of an ellipse in the standard form is $${4 \over {\sqrt 3 }}$$. If this ellipse touches the line, x + 6y = 8; then its eccentricity is :
A
$${1 \over 3}\sqrt {{{11} \over 3}} $$
B
$${1 \over 2}\sqrt {{5 \over 3}} $$
C
$$\sqrt {{5 \over 6}} $$
D
$${1 \over 2}\sqrt {{{11} \over 3}} $$
4
JEE Main 2020 (Online) 9th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A random variable X has the following probability distribution :

X: 1 2 3 4 5
P(X): K2 2K K 2K 5K2

Then P(X > 2) is equal to :
A
$${1 \over {6}}$$
B
$${7 \over {12}}$$
C
$${1 \over {36}}$$
D
$${23 \over {36}}$$
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