1
JEE Main 2019 (Online) 10th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The type of hybridisation and number of lone pair (s) of electrons of Xe in XeOF4, respectively, are:
A
sp3d and 2
B
sp3d2 and 2
C
sp3d and 1
D
sp3d2 and 1
2
JEE Main 2019 (Online) 10th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Consider the following reduction processes :
Zn2+ + 2e $$ \to $$ Zn(s) ; Eo = – 0.76 V
Ca2+ + 2e $$ \to $$ Ca(s); Eo = –2.87 V
Mg2+ + 2e $$ \to $$ Mg(s) ; Eo = – 2.36 V
Ni2 + 2e $$ \to $$ Ni(s) ; Eo = – 0.25
The reducing power of the metals increases in the order :
A
Ca < Mg < Zn < Ni
B
Ni < Zn < Mg < Ca
C
Zn < Mg < Ni < Ca
D
Ca < Zn < Mg < Ni
3
JEE Main 2019 (Online) 10th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product formed in the reaction given below will be :

JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Compounds Containing Nitrogen Question 167 English
A
JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Compounds Containing Nitrogen Question 167 English Option 1
B
JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Compounds Containing Nitrogen Question 167 English Option 2
C
JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Compounds Containing Nitrogen Question 167 English Option 3
D
JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Compounds Containing Nitrogen Question 167 English Option 4
4
JEE Main 2019 (Online) 10th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Liquids A and B form an ideal solution in the entire composition range. At 350 K, the vaapor pressures of pure A and pure B are 7 $$ \times $$ 103 Pa and 12 $$ \times $$ 103 Pa, respectively . The composition of the vapor in equilibriumwith a solution containing 40 mole percent of A at this temperature is :
A
xA = 0.76; xB = 0.24
B
xA = 0.28; xB = 0.72
C
xA = 0.4; xB = 0.6
D
xA = 0.37; xB = 0.63
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