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JEE Main 2017 (Online) 9th April Morning Slot
MCQ (Single Correct Answer)
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Four closed surfaces and corresponding charge distributions are shown below.

JEE Main 2017 (Online) 9th April Morning Slot Physics - Electrostatics Question 210 English

Let the respective electric fluxes through the surfaces be $${\Phi _1},$$ $${\Phi _2},$$ $${\Phi _3}$$ and $${\Phi _4}$$. Then :
A
$${\Phi _1}$$ < $${\Phi _2}$$ = $${\Phi _3}$$ > $${\Phi _4}$$
B
$${\Phi _1}$$ > $${\Phi _2}$$ > $${\Phi _3}$$ > $${\Phi _4}$$
C
$${\Phi _1}$$ = $${\Phi _2}$$ = $${\Phi _3}$$ = $${\Phi _4}$$
D
$${\Phi _1}$$ > $${\Phi _3}$$ ; $${\Phi _2}$$ < $${\Phi _4}$$
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