1
JEE Main 2016 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
A pendulum clock loses $$12$$ $$s$$ a day if the temperature is $${40^ \circ }C$$ and gains $$4$$ $$s$$ a day if the temperature is $${20^ \circ }C.$$ The temperature at which the clock will show correct time, and the co-efficient of linear expansion $$\left( \alpha \right)$$ of the metal of the pendulum shaft are respectively :
A
$${30^ \circ }C;\,\,\alpha = 1.85 \times {10^{ - 3}}/{}^ \circ C$$
B
$${55^ \circ }C;\,\,\alpha = 1.85 \times {10^{ - 2}}/{}^ \circ C$$
C
$${25^ \circ }C;\,\,\alpha = 1.85 \times {10^{ - 5}}/{}^ \circ C$$
D
$${60^ \circ }C;\,\,\alpha = 1.85 \times {10^{ - 4}}/{}^ \circ C$$
2
JEE Main 2016 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
A roller is made by joining together two cones at their vertices $$0$$. It is kept on two rails $$AB$$ and $$CD$$, which are placed asymmetrically (see figure), with its axis perpendicular to $$CD$$ and its center $$O$$ at the center of line joining $$AB$$ and $$CD$$ (see figure). It is given a light push so that it starts rolling with its center $$O$$ moving parallel to $$CD$$ in the direction shown. As it moves, the roller will tend to : JEE Main 2016 (Offline) Physics - Rotational Motion Question 180 English
A
go straight
B
turn left and right alternately
C
turn left
D
turn right
3
JEE Main 2016 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
$$'n'$$ moles of an ideal gas undergoes a process $$A$$ $$ \to $$ $$B$$ as shown in the figure. The maximum temperature of the gas during the process will be :

JEE Main 2016 (Offline) Physics - Heat and Thermodynamics Question 330 English
A
$${{9{P_0}{V_0}} \over {2nR}}$$
B
$${{9{P_0}{V_0}} \over {nR}}$$
C
$${{9{P_0}{V_0}} \over {4nR}}$$
D
$${{3{P_0}{V_0}} \over {2nR}}$$
4
JEE Main 2016 (Offline)
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle performs simple harmonic motion with amplitude $$A.$$ Its speed is trebled at the instant that it is at a distance $${{2A} \over 3}$$ from equilibrium position. The new amplitude of the motion is:
A
$$A\sqrt 3 $$
B
$${{7A} \over 3}$$
C
$${A \over 3}\sqrt {41} $$
D
$$3A$$
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