Match List I with List II
LIST I (Molecule/Species) |
LIST II (Property/Shape) |
||
---|---|---|---|
A. | $$\mathrm{SO_2Cl_2}$$ | I. | Paramagnetic |
B. | $$\mathrm{NO}$$ | II. | Diamagnetic |
C. | $$\mathrm{NO_2^-}$$ | III. | Tetrahedral |
D. | $$\mathrm{I_3^-}$$ | IV. | Linear |
Choose the correct answer from the options given below:
Match List I with List II.
LIST I |
LIST II |
||
---|---|---|---|
A. | $$ \mathrm{ICl} $$ |
I. | T - shape |
B. | $$ \mathrm{ICl}_3 $$ |
II. | Square pyramidal |
C. | $$ \mathrm{ClF}_5 $$ |
III. | Pentagonal bipyramidal |
D. | $$ \mathrm{IF}_7 $$ |
IV. | Linear |
Choose the correct answer from the options given below :
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : $$\mathrm{NH}_3$$ and $$\mathrm{NF}_3$$ molecule have pyramidal shape with a lone pair of electrons on nitrogen atom. The resultant dipole moment of $$\mathrm{NH}_3$$ is greater than that of $$\mathrm{NF}_3$$.
Reason (R) : In $$\mathrm{NH}_3$$, the orbital dipole due to lone pair is in the same direction as the resultant dipole moment of the $$\mathrm{N}-\mathrm{H}$$ bonds. $$\mathrm{F}$$ is the most electronegative element.
In the light of the above statements, choose the correct answer from the options given below :
Number of $$\sigma$$ and $$\pi$$ bonds present in ethylene molecule is respectively :