1
JEE Main 2024 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II

LIST I
(Molecule/Species)
LIST II
(Property/Shape)
A. $$\mathrm{SO_2Cl_2}$$ I. Paramagnetic
B. $$\mathrm{NO}$$ II. Diamagnetic
C. $$\mathrm{NO_2^-}$$ III. Tetrahedral
D. $$\mathrm{I_3^-}$$ IV. Linear

Choose the correct answer from the options given below:

A
A-II, B-III, C-I, D-IV
B
A-III, B-I, C-II, D-IV
C
A-IV, B-I, C-III, D-II
D
A-III, B-IV, C-II, D-I
2
JEE Main 2024 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Match List I with List II.

LIST I
LIST II
A. $$
\mathrm{ICl}
$$
I. T - shape
B. $$
\mathrm{ICl}_3
$$
II. Square pyramidal
C. $$
\mathrm{ClF}_5
$$
III. Pentagonal bipyramidal
D. $$
\mathrm{IF}_7
$$
IV. Linear

Choose the correct answer from the options given below :

A
(A)-(I), (B)-(IV), (C)-(III), (D)-(II)
B
(A)-(IV), (B)-(I), (C)-(II), (D)-(III)
C
(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
D
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
3
JEE Main 2024 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : $$\mathrm{NH}_3$$ and $$\mathrm{NF}_3$$ molecule have pyramidal shape with a lone pair of electrons on nitrogen atom. The resultant dipole moment of $$\mathrm{NH}_3$$ is greater than that of $$\mathrm{NF}_3$$.

Reason (R) : In $$\mathrm{NH}_3$$, the orbital dipole due to lone pair is in the same direction as the resultant dipole moment of the $$\mathrm{N}-\mathrm{H}$$ bonds. $$\mathrm{F}$$ is the most electronegative element.

In the light of the above statements, choose the correct answer from the options given below :

A
(A) is false but (R) is true
B
(A) is true but (R) is false
C
Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
D
Both (A) and (R) are true and (R) is the correct explanation of (A)
4
JEE Main 2024 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Number of $$\sigma$$ and $$\pi$$ bonds present in ethylene molecule is respectively :

A
3 and 1
B
5 and 1
C
4 and 1
D
5 and 2
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