JEE Main 2024 (Online) 5th April Morning Shift | Wave Optics Question 54 | Physics

The width of one of the two slits in a Young's double slit experiment is 4 times that of the other slit. The ratio of the maximum of the minimum intensity in the interference pattern is:

$$1: 1$$

$$4: 1$$

$$16: 1$$

$$9: 1$$

JEE Main 2024 (Online) 1st February Evening Shift

MCQ (Single Correct Answer)

-1

A microwave of wavelength $2.0 \mathrm{~cm}$ falls normally on a slit of width $4.0 \mathrm{~cm}$. The angular spread of the central maxima of the diffraction pattern obtained on a screen $1.5 \mathrm{~m}$ away from the slit, will be :

$60^{\circ}$

$45^{\circ}$

$15^{\circ}$

$30^{\circ}$

JEE Main 2024 (Online) 1st February Morning Shift

MCQ (Single Correct Answer)

-1

A monochromatic light of wavelength $6000 ~\mathring{A}$ is incident on the single slit of width $0.01 \mathrm{~mm}$. If the diffraction pattern is formed at the focus of the convex lens of focal length $20 \mathrm{~cm}$, the linear width of the central maximum is :

$12 \mathrm{~mm}$

$24 \mathrm{~mm}$

$60 \mathrm{~mm}$

$120 \mathrm{~mm}$

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