JEE Main 2019 (Online) 12th April Morning Slot | Wave Optics Question 92 | Physics

In a double slit experiment, when a thin film of thickness t having refractive index $$\mu $$. is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is ($$\lambda $$ is the wavelength of the light used) :

$${\lambda \over {2\left( {\mu - 1} \right)}}$$

$${\lambda \over {\left( {2\mu - 1} \right)}}$$

$${{2\lambda } \over {\left( {\mu - 1} \right)}}$$

$${\lambda \over {\left( {\mu - 1} \right)}}$$

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

The value of numerical aperature of the objective lens of a microscope is 1.25. If light of wavelength 5000 $$\mathop A\limits^o $$ is used, the minimum separation between two points, to be seen as distinct, will be :

0.12 $$\mu $$m

0.38 $$\mu $$m

0.24 $$\mu $$m

0.48 $$\mu $$m

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

In a Young's double slit experiment, the ratio of the slit's width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be :

25 : 9

4 : 1

$${\left( {\sqrt 3 + 1} \right)^4}:16$$

9 : 1

JEE Main 2019 (Online) 9th April Evening Slot

MCQ (Single Correct Answer)

-1

Diameter of the objective lens of a telescope is 250 cm. For light of wavelength 600nm. coming from a distant object, the limit of resolution of the telescope is close to :-

3.0 × 10^–7 rad

4.5 × 10^–7 rad

1.5 × 10^–7 rad

2.0 × 10^–7 rad

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