JEE Main 2019 (Online) 10th April Evening Slot | Wave Optics Question 115 | Physics

In a Young's double slit experiment, the ratio of the slit's width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be :

25 : 9

4 : 1

$${\left( {\sqrt 3 + 1} \right)^4}:16$$

9 : 1

JEE Main 2019 (Online) 9th April Evening Slot

MCQ (Single Correct Answer)

-1

Diameter of the objective lens of a telescope is 250 cm. For light of wavelength 600nm. coming from a distant object, the limit of resolution of the telescope is close to :-

3.0 × 10^–7 rad

4.5 × 10^–7 rad

1.5 × 10^–7 rad

2.0 × 10^–7 rad

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

The figure shows a Young's double slit experimental setup. It is observed that when a thin transparent sheet of thickness t and refractive index μ is put in front of one of the slits, the central maximum gest shifted by a distance equal to n fringe widths. If the wavelength of light used is $$\lambda $$, t will be : JEE Main 2019 (Online) 9th April Morning Slot Physics - Wave Optics Question 117 English

JEE Main 2019 (Online) 9th April Morning Slot Physics - Wave Optics Question 117 English

$${{D\lambda } \over {a\left( {\mu - 1} \right)}}$$

$${{2nD\lambda } \over {a\left( {\mu - 1} \right)}}$$

$${{2D\lambda } \over {a\left( {\mu - 1} \right)}}$$

$${{n\lambda } \over {\left( {\mu - 1} \right)}}$$

JEE Main 2019 (Online) 8th April Evening Slot

MCQ (Single Correct Answer)

-1

Calculate the limit of resolution of a telescope objective having a diameter of 200 cm, if it has to detect light of wavelength 500 nm coming from a star :-

610 × 10^–9 radian

457.5 × 10^–9 radian

305 × 10^–9 radian

152.5 × 10^–9 radian

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