1
JEE Main 2014 (Offline)
+4
-1
Two beams, $$A$$ and $$B$$, of plane polarized light with mutually perpendicular planes of polarization are seen through a polaroid. From the position when the beam $$A$$ has maximum intensity (and beam $$B$$ has zero intensity), a rotation of polaroid through $${30^ \circ }$$ makes the two beams appear equally bright. If the initial intensities of the two beams are $${{\rm I}_A}$$ and $${{\rm I}_B}$$ respectively, then $${{{{\rm I}_A}} \over {{{\rm I}_B}}}$$ equals:
A
$$3$$
B
$${3 \over 2}$$
C
$$1$$
D
$${1 \over 3}$$
2
JEE Main 2013 (Offline)
+4
-1
A beam of unpolarised light of intensity $${{\rm I}_0}$$ is passed through a polaroid $$A$$ and then through another polaroid $$B$$ which is oriented so that its principal plane makes an angle of $${45^ \circ }$$ relative to that of $$A$$. The intensity of the emergent light is
A
$${{\rm I}_0}$$
B
$${{{I_0}} \over 2}$$
C
$${{{I_0}} \over 4}$$
D
$${{{I_0}} \over 8}$$
3
JEE Main 2013 (Offline)
+4
-1
Two coherent point sources $${S_1}$$ and $${S_2}$$ are separated by a small distance $$'d'$$ as shown. The fringes obtained on the screen will be

A
points
B
straight lines
C
semi-circles
D
concentric circles
4
AIEEE 2012
+4
-1
In Young's double slit experiment , one of the slit is wider than other, so that amplitude of the light from one slit is double of that from other slit. If $${{\rm I}_m}$$ be the maximum intensity, the resultant intensity $${\rm I}$$ when they interfere at phase difference $$\phi$$ is given by :
A
$${{{I_m}} \over 9}\left( {4 + 5\cos \,\phi } \right)$$
B
$${{{I_m}} \over 3}\left( {1 + 2{{\cos }^2}\,{\phi \over 2}} \right)$$
C
$${{{I_m}} \over 3}\left( {1 + 4{{\cos }^2}\,{\phi \over 2}} \right)$$
D
$${{{I_m}} \over 9}\left( {1 + 8{{\cos }^2}\,{\phi \over 2}} \right)$$
EXAM MAP
Medical
NEET