1
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
A polarizer - analyser set is adjusted such that the intensity of light coming out of the analyser is just 10% of the original intensity. Assuming that the polarizer - analyser set does not absorb any light, the angle by which the analyser need to be rotated further to reduce the output intensity to be zero, is :
A
71.6o
B
90o
C
18.4o
D
45o
2
JEE Main 2020 (Online) 7th January Morning Slot
+4
-1
Visible light of wavelength 6000 $$\times$$ 10-8 cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60o from the central maximum. If the first minimum is produced at $$\theta$$1, then $$\theta$$1, is close to :
A
45o
B
30o
C
25o
D
20o
3
JEE Main 2019 (Online) 12th April Evening Slot
+4
-1
A system of three polarizers P1, P2, P3 is set up such that the pass axis of P3 is crossed with respect to that of P1. The pass axis of P2 is inclined at 60o to the pass axis of P3. When a beam of unpolarized light of intensity I0 is incident on P1, the intensity of light transmitted by the three polarizers is I. The ratio ($${{{I_0}} \over I}$$) equals (nearly) :
A
10.67
B
5.33
C
16.00
D
1.80
4
JEE Main 2019 (Online) 12th April Morning Slot
+4
-1
The value of numerical aperature of the objective lens of a microscope is 1.25. If light of wavelength 5000 $$\mathop A\limits^o$$ is used, the minimum separation between two points, to be seen as distinct, will be :
A
0.12 $$\mu$$m
B
0.38 $$\mu$$m
C
0.24 $$\mu$$m
D
0.48 $$\mu$$m
EXAM MAP
Medical
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