1
JEE Main 2023 (Online) 1st February Morning Shift
+4
-1

'$$n$$' polarizing sheets are arranged such that each makes an angle $$45^{\circ}$$ with the preceeding sheet. An unpolarized light of intensity I is incident into this arrangement. The output intensity is found to be $$I / 64$$. The value of $$n$$ will be:

A
4
B
5
C
3
D
6
2
JEE Main 2023 (Online) 31st January Morning Shift
+4
-1

Two polaroide $$\mathrm{A}$$ and $$\mathrm{B}$$ are placed in such a way that the pass-axis of polaroids are perpendicular to each other. Now, another polaroid $$\mathrm{C}$$ is placed between $$\mathrm{A}$$ and $$\mathrm{B}$$ bisecting angle between them. If intensity of unpolarized light is $$\mathrm{I}_{0}$$ then intensity of transmitted light after passing through polaroid $$\mathrm{B}$$ will be:

A
$$\frac{I_{0}}{4}$$
B
$$\frac{I_{0}}{8}$$
C
Zero
D
$$\frac{I_{0}}{2}$$
3
JEE Main 2023 (Online) 29th January Morning Shift
+4
-1

In a Young's double slit experiment, two slits are illuminated with a light of wavelength $$800 \mathrm{~nm}$$. The line joining $$A_{1} P$$ is perpendicular to $$A_{1} A_{2}$$ as shown in the figure. If the first minimum is detected at $$P$$, the value of slits separation 'a' will be:

The distance of screen from slits D = 5 cm

A
0.2 mm
B
0.5 mm
C
0.4 mm
D
0.1 mm
4
JEE Main 2023 (Online) 25th January Morning Shift
+4
-1

In Young's double slits experiment, the position of 5$$\mathrm{^{th}}$$ bright fringe from the central maximum is 5 cm. The distance between slits and screen is 1 m and wavelength of used monochromatic light is 600 nm. The separation between the slits is :

A
60 $$\mu$$m
B
48 $$\mu$$m
C
36 $$\mu$$m
D
12 $$\mu$$m
EXAM MAP
Medical
NEET