Consider the following sequence of reactions

The major product P is :

Consider compounds $\mathrm{A}, \mathrm{B}$ and C with following structural formulae

$$ \begin{aligned} & \mathrm{A}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH} \\ & \mathrm{~B}=\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_3 \\ & \mathrm{C}=\mathrm{HO}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}(\mathrm{OH})-\mathrm{CH}_3 \end{aligned} $$

For the conversion of B from A , reagent (D) required is $\_\_\_\_$ and structural formula of product $(\mathrm{E})$ obtained when C undergoes same reaction using excess reagent (D) is $\_\_\_\_$ .

$$ \text { Identify the colour of compound ' } \mathrm{X} \text { ' in the sequence of the reaction. } $$

The reactions which produce alcohol as the product are :

A. $\mathrm{CH}_4 + \mathrm{O}_2 \xrightarrow{\mathrm{Mo}_2\mathrm{O}_3,\ \Delta} $

B. $2\mathrm{CH}_3\mathrm{CH}_3 + 3\mathrm{O}_2 \xrightarrow{(\mathrm{CH}_3\mathrm{COO})_2\mathrm{Mn},\ \Delta} $

C. $(\mathrm{CH}_3)_3\mathrm{CH} \xrightarrow{\mathrm{KMnO}_4} $

D. $ 2\mathrm{CH}_4 + \mathrm{O}_2 \xrightarrow{\mathrm{Cu}/523\ \mathrm{K}/100 \ \mathrm{atm}.} $

E. $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3 \xrightarrow{\mathrm{KMnO}_4/\mathrm{H}^+} $

Choose the correct answer from the options given below :