The major product obtained in the following reaction is :
In LiAlH4, H- is the attacking species which is a strong nucleophile and performs both nucleophilc substitution and nucleophilic addition reaction. In C = C, pi bond is created by pure p orbital with side by side overlapping which create $$\pi $$ cloud and $$\pi $$ cloud creates negative charge around it. As H- is also negative charged so LiAlH4 can't reduce C = C.
MCQ (Single Correct Answer)
JEE Main 2019 (Online) 11th January Evening Slot
The major product obtained in the following conversion is
In Formaldehyde (HCHO) both side of the C atom H presents but in Acetaldehyde (CH3CHO) one side of C atom -CH3 group and other side H atom presents. So Formaldehyde is less crowded then it is more reactive.
CH3OH is 1o alcohol and tBuOH is 3o alcohol. As we know on 3o alcohol steric hindrance is very high compare to 1o alcohol and due to steric hindrance reactivity of 3o alcohol is less compare to 1o alcohol.
Questions Asked from Aldehydes, Ketones and Carboxylic Acids
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