$$ \text { Match the LIST-I with LIST-II } $$
| $$ \begin{gathered} \text { List-I } \\ \text { Name of reaction } \end{gathered} $$ |
$$ \begin{gathered} \text { List-II } \\ \text { Reagent or catalyst used } \end{gathered} $$ |
||
|---|---|---|---|
| A. | Finkelstein reaction | I. | $\mathrm{SbF}_3$ |
| B. | Swarts reaction | II. | Na, dry ether |
| C. | Sandmeyer's reaction | III. | NaI |
| D. | Fittig reaction | IV. | $\mathrm{Cu}_2 \mathrm{Cl}_2$ |
Choose the correct answer from the options given below :
Correct statements regarding alkyl halides (R–X) among the following are :
A. Alcohol being less polar solvent as compared to water, alcoholic KOH favours elimination reaction with R–X.
B. Order of reactivity towards SN1 mechanism is C6H5–CH2–Cl > C6H5–CHCl–C6H5.
C. Non substituted aryl halides exhibit properties similar to alkyl halides.
D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne.
E. R–Cl can be prepared by reacting R–OH with SOCl2 but Ar–Cl cannot be prepared by reacting Ar–OH with SOCl2.
Choose the correct answer from the options given below :
Given below are two statements :
Statement (I) : Benzyl chloride reacts faster in $S_N1$ mechanism than ethyl chloride.
Statement (II) : Ethyl carbocation intermediate is less stabilized by hyperconjugation than benzyl carbocation by resonance.
In the light of the above statements, choose the correct answer from the options given below :
Consider the above reaction
A. The reaction proceeds through a more stable radical intermediate.
B. The role of peroxide is to generate $${H^ \bullet }$$ (Hydrogen radical).
C. During this reaction, benzene is formed as a byproduct.
D. 1-Bromo-2-phenylethane is formed as the minor product.
E. The same reaction in absence of peroxide proceeds via carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below :
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