1
JEE Main 2020 (Online) 7th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the following reactions

JEE Main 2020 (Online) 7th January Evening Slot Chemistry - Haloalkanes and Haloarenes Question 99 English
Ks and Ke, are respectively, the rate constants for substitution and elimination and $$\mu = {{{k_s}} \over {{k_e}}}$$ the correct options is
A
$${\mu _B} > {\mu _A}$$ and Ke(A) > Ke(B)
B
$${\mu _A} > {\mu _B}$$ and Ke(B) > Ke(A)
C
$${\mu _B} > {\mu _A}$$ and Ke(B) > Ke(A)
D
$${\mu _A} > {\mu _B}$$ and Ke(A) > Ke(B)
2
JEE Main 2020 (Online) 7th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
1- methyl ethylene oxide when treated with an excess of HBr produces :
A
JEE Main 2020 (Online) 7th January Morning Slot Chemistry - Haloalkanes and Haloarenes Question 101 English Option 1
B
JEE Main 2020 (Online) 7th January Morning Slot Chemistry - Haloalkanes and Haloarenes Question 101 English Option 2
C
JEE Main 2020 (Online) 7th January Morning Slot Chemistry - Haloalkanes and Haloarenes Question 101 English Option 3
D
JEE Main 2020 (Online) 7th January Morning Slot Chemistry - Haloalkanes and Haloarenes Question 101 English Option 4
3
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
An 'Assertion' and a 'Reason' are given below. Choose the correct answer from the following options :
Assertion (A) : Vinyl halides do not undergo nucleophilic substitution easily.
Reason (R) : Even though the intermediate carbocation is stabilized by loosely held p-electrons, the cleavage is difficult because of strong bonding.
A
Both (A) and (R) are correct statements but (R) is not the correct explanation of (A)
B
Both (A) and (R) are correct statements and (R) is the correct explanation of (A)
C
(A) is correct statement but (R) is a wrong statement
D
Both (A) and (R) are wrong statements.
4
JEE Main 2019 (Online) 12th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Heating of 2-chloro-1-phenylbutane with EtOK/EtOH gives X as the major product. Reaction of X with Hg(OAc)2/H2O followed by NaBH4 gives Y as the major product. Y is :
A
JEE Main 2019 (Online) 12th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 103 English Option 1
B
JEE Main 2019 (Online) 12th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 103 English Option 2
C
JEE Main 2019 (Online) 12th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 103 English Option 3
D
JEE Main 2019 (Online) 12th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 103 English Option 4
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