1
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line. One may conclude that :
A
$$R(T) = {R_0}{e^{ - {T^2}/T_0^2}}$$
B
$$R(T) = {{{R_0}} \over {{T^2}}}$$
C
$$R(T) = {R_0}{e^{ {T^2}/T_0^2}}$$
D
$$R(T) = {R_0}{e^{ - T_0^2/{T^2}}}$$
2
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
A moving coil galvanometer allows a full scale current of 10–4 A. A series resistance of 2 M$$\Omega$$ is required to convert the above galvanometer into a voltmeter of range 0-5 V. Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0.10 mA is :
A
200 $$\Omega$$
B
500 $$\Omega$$
C
100 $$\Omega$$
D
None of the options are correct
3
JEE Main 2019 (Online) 10th April Morning Slot
+4
-1
In the given circuit, an ideal voltmeter connected across the 10$$\Omega$$ resistance reads 2V. The internal resistance r, of each cell is:
A
1.5 $$\Omega$$
B
1 $$\Omega$$
C
0.5 $$\Omega$$
D
0 $$\Omega$$
4
JEE Main 2019 (Online) 9th April Evening Slot
+4
-1
A metal wire of resistance 3 $$\Omega$$ is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60° at the centre, the equivalent resistance between these two points will be :-
A
5 /2 $$\Omega$$
B
12/5 $$\Omega$$
C
7/2 $$\Omega$$
D
5 / 3 $$\Omega$$
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