Two p-block elements X and Y form fluorides of the type $\mathrm{EF}_3$. The fluoride compound $\mathrm{XF}_3$ is a Lewis acid and $\mathrm{YF}_3$ is a Lewis base. The hybridizations of the central atoms of $\mathrm{XF}_3$ and $\mathrm{YF}_3$ respectively are

A first row transition metal $(\mathrm{M})$ does not liberate $\mathrm{H}_2$ gas from dilute HCl .1 mol of aqueous solution of $\mathrm{MSO}_4$ is treated with excess of aqueous KCN and then $\mathrm{H}_2 \mathrm{~S}(\mathrm{~g})$ is passed through the solution. The amount of MS (metal sulphide) formed from the above reaction is $\_\_\_\_$ mol.

$$ \text { Match the LIST-I with LIST-II } $$

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<mn>3</mn>

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<mn>3</mn>

<mrow data-mjx-texclass="ORD">

  <mi data-mjx-auto-op="false">dm</mi>

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<mn>3</mn>

<mrow data-mjx-texclass="ORD">

  <mi data-mjx-auto-op="false">dm</mi>

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<mn>3</mn>

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<mn>3</mn>

<mrow data-mjx-texclass="ORD">

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<mn>3</mn>

<mrow data-mjx-texclass="ORD">

  <mtext> </mtext>

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<mn>3</mn>

<mrow data-mjx-texclass="ORD">

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<mn>3</mn>

<mtext> </mtext>

<mi mathvariant="normal">K</mi>

<mtext></mtext>

<mi mathvariant="normal">K</mi>

<mover>

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  <mo accent="true">―</mo>

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<mrow data-mjx-texclass="ORD">

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    <mi mathvariant="normal">V</mi>

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<mn>3</mn>

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<mi mathvariant="normal">R</mi>

<mover accentunder="false">

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    <mi mathvariant="normal">C</mi>

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  <mo>¯</mo>

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    <mi mathvariant="normal">V</mi>

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<mn>3</mn>

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<mi mathvariant="normal">R</mi>

<mtext> </mtext>

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<mtext></mtext>

<mi mathvariant="normal">K</mi>

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<mn>5</mn>

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<mi mathvariant="normal">R</mi>

<mover accentunder="false">

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  <mo>¯</mo>

</mover>

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<mn>5</mn>

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<mi mathvariant="normal">R</mi>

'A' is a neutral organic compound (M. F : $\mathrm{C}_8 \mathrm{H}_9 \mathrm{ON}$ ). On treatment with aqueous $\mathrm{Br}_2 / \mathrm{HO}^{(-)}$, ' A ' forms a compound ' B ' which is soluble in dilute acid. ' B ' on treatment with aqueous $\mathrm{NaNO}_2 / \mathrm{HCl}\left(0-5^{\circ} \mathrm{C}\right)$ produces a compound ' C ' which on treatment with $\mathrm{CuCN} / \mathrm{NaCN}$ produces ' D '. Hydrolysis of ' D ' produces ' E ' which is also obtainable from the hydrolysis of ' A '. ' E ' on treatment with acidified $\mathrm{KMnO}_4$ produces ' F '. ' F ' contains two different types of hydrogen atoms. The structure of ' A ' is