1
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
The correct order of electron gain enthalpy is :
A
Te > Se > S > O
B
S > Se > Te > O
C
S > O > Se > Te
D
O > S > Se > Te
2
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Match List - I with List - II.

List - I List - II
(a) Sucrose (i) $$\beta $$-D-Galactose and $$\beta $$-D-Glucose
(b) Lactose (ii) $$\alpha $$-D-Glucose and $$\beta $$-D-Fructose
(c) Maltose (iii) $$\alpha $$-D-Glucose and $$\alpha $$-D-Glucose

Choose the correct answer from the options given below :
A
(a) $$ \to $$ (iii), (b) $$ \to $$ (ii), (c) $$ \to $$ (i)
B
(a) $$ \to $$ (i), (b) $$ \to $$ (iii), (c) $$ \to $$ (ii)
C
(a) $$ \to $$ (ii), (b) $$ \to $$ (i), (c) $$ \to $$ (iii)
D
(a) $$ \to $$ (iii), (b) $$ \to $$ (i), (c) $$ \to $$ (ii)
3
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Seliwanoff test and Xanthoproteic test are used for the identification of ___________ and ________ respectively.
A
ketoses, proteins
B
proteins, ketoses
C
aldoses, ketoses
D
ketoses, aldoses
4
JEE Main 2021 (Online) 26th February Evening Shift
Numerical
+4
-1
Change Language
When 12.2 g of benzoic acid is dissolved in 100 g of water, the freezing point of solution was found to be $$-$$0.93$$^\circ$$C (Kf(H2O) = 1.86 K kg mol$$-$$1). The number (n) of benzoic acid molecules associated (assuming 100% association) is ___________.
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