1
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
In an electromagnetic wave the electric field vector and magnetic field vector are given as $$\overrightarrow E = {E_0}\widehat i$$ and $$\overrightarrow B = {B_0}\widehat k$$ respectively. The direction of propagation of electromagnetic wave is along :
A
$$\left( {\widehat k} \right)$$
B
$$\widehat j$$
C
$$\left( { - \widehat k} \right)$$
D
$$\left( { - \widehat j} \right)$$
2
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
For a series LCR circuit with R = 100 $$\Omega$$, L = 0.5 mH and C = 0.1 pF connected across 220V$$-$$50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is :
A
0$$^\circ$$, resistive circuit
B
$$ \approx $$ 90$$^\circ$$, predominantly inductive circuit
C
0$$^\circ$$, resonance circuit
D
$$ \approx $$ 90$$^\circ$$, predominantly capacitive circuit
3
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Which of the following graphs represent the behavior of an ideal gas? Symbols have their usual meaning.
A
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 190 English Option 1
B
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 190 English Option 2
C
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 190 English Option 3
D
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 190 English Option 4
4
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle is making simple harmonic motion along the X-axis. If at a distances x1 and x2 from the mean position the velocities of the particle are v1 and v2 respectively. The time period of its oscillation is given as :
A
$$T = 2\pi \sqrt {{{x_2^2 + x_1^2} \over {v_1^2 - v_2^2}}} $$
B
$$T = 2\pi \sqrt {{{x_2^2 + x_1^2} \over {v_1^2 + v_2^2}}} $$
C
$$T = 2\pi \sqrt {{{x_2^2 - x_1^2} \over {v_1^2 + v_2^2}}} $$
D
$$T = 2\pi \sqrt {{{x_2^2 - x_1^2} \over {v_1^2 - v_2^2}}} $$
JEE Main Papers
2023
2021
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12