1
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
In an electromagnetic wave the electric field vector and magnetic field vector are given as $$\overrightarrow E = {E_0}\widehat i$$ and $$\overrightarrow B = {B_0}\widehat k$$ respectively. The direction of propagation of electromagnetic wave is along :
A
$$\left( {\widehat k} \right)$$
B
$$\widehat j$$
C
$$\left( { - \widehat k} \right)$$
D
$$\left( { - \widehat j} \right)$$
2
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
For a series LCR circuit with R = 100 $$\Omega$$, L = 0.5 mH and C = 0.1 pF connected across 220V$$-$$50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is :
A
0$$^\circ$$, resistive circuit
B
$$ \approx $$ 90$$^\circ$$, predominantly inductive circuit
C
0$$^\circ$$, resonance circuit
D
$$ \approx $$ 90$$^\circ$$, predominantly capacitive circuit
3
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
Which of the following graphs represent the behavior of an ideal gas? Symbols have their usual meaning.
A
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 167 English Option 1
B
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 167 English Option 2
C
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 167 English Option 3
D
JEE Main 2021 (Online) 20th July Evening Shift Physics - Heat and Thermodynamics Question 167 English Option 4
4
JEE Main 2021 (Online) 20th July Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
A particle is making simple harmonic motion along the X-axis. If at a distances x1 and x2 from the mean position the velocities of the particle are v1 and v2 respectively. The time period of its oscillation is given as :
A
$$T = 2\pi \sqrt {{{x_2^2 + x_1^2} \over {v_1^2 - v_2^2}}} $$
B
$$T = 2\pi \sqrt {{{x_2^2 + x_1^2} \over {v_1^2 + v_2^2}}} $$
C
$$T = 2\pi \sqrt {{{x_2^2 - x_1^2} \over {v_1^2 + v_2^2}}} $$
D
$$T = 2\pi \sqrt {{{x_2^2 - x_1^2} \over {v_1^2 - v_2^2}}} $$
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