1
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Two identical strings X and Z made of same material have tension TX and TZ in them. If their fundamental frequencies are 450 Hz and 300 Hz, respectively, then the ratio TX/TZ is
A
2.25
B
0.44
C
1.25
D
1.5
2
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Interference fringes are observed on a screen by illuminating two thin slits 1 mm apart with a light source ($$\lambda $$ = 632.8 nm). The distance between the screen and the slits is 100 cm. If a bright fringe is observed on a screen at a distance of 1.27 mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close is
A
1.27 $$\mu $$m
B
2.05 $$\mu $$m
C
2.87 nm
D
2 nm
3
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A cylindrical vessel containing a liquid is rotated about its axis so that the liquid rises at its sides as shown in the figure. The radius of vessel is 5 cm and the angular speed of rotation is $$\omega $$ rad s–1. The difference in the height, h (in cm) of liquid at the centre of vessel and at the side will be : JEE Main 2020 (Online) 2nd September Morning Slot Physics - Properties of Matter Question 181 English
A
$${{2{\omega ^2}} \over {25g}}$$
B
$${{5{\omega ^2}} \over {2g}}$$
C
$${{25{\omega ^2}} \over {2g}}$$
D
$${{2{\omega ^2}} \over {5g}}$$
4
JEE Main 2020 (Online) 2nd September Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
A charged particle (mass m and charge q)
moves along X-axis with velocity V0. When it
passes through the origin it enters a region having uniform electric field
$$\overrightarrow E = - E\widehat j$$ which extends upto x = d.
Equation of path of electron in the region x > d is JEE Main 2020 (Online) 2nd September Morning Slot Physics - Electrostatics Question 136 English
A
y = $${{qEd} \over {mV_0^2}}\left( {x - d} \right)$$
B
y = $${{qEd} \over {mV_0^2}}\left( {{d \over 2} - x} \right)$$
C
y = $${{qEd} \over {mV_0^2}}x$$
D
y = $${{qE{d^2}} \over {mV_0^2}}x$$
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