1
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Calculate the standard cell potential in (V) of the cell in which following reaction takes place :

Fe2+(aq) + Ag+(aq) $$ \to $$ Fe3+(aq) + Ag (s)

Given that

$$E_{A{g^ + }/Ag}^o = xV$$

$$E_{Fe^{2+ }/Fe}^o = yV$$

$$E_{Fe^{3+ }/Fe}^o = zV$$
A
x + 2y - 3z
B
x - z
C
x - y
D
x + y - z
2
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product in the following reaction is : JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 115 English
A
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 115 English Option 1
B
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 115 English Option 2
C
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 115 English Option 3
D
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Haloalkanes and Haloarenes Question 115 English Option 4
3
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For the following reactions, equilibrium constants are given :

S(s) + O2(g) ⇋ SO2(g); K1 = 1052

2S(s) + 3O2(g) ⇋ 2SO3(g); K2 = 10129

The equilibrium constant for the reaction,

2SO2(g) + O2(g) ⇋ 2SO3(g) is :
A
10181
B
1025
C
1077
D
10154
4
JEE Main 2019 (Online) 8th April Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The structure of Nylon-6 is :
A
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Polymers Question 56 English Option 1
B
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Polymers Question 56 English Option 2
C
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Polymers Question 56 English Option 3
D
JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Polymers Question 56 English Option 4
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