JEE Main 2018 (Online) 15th April Morning Slot | Solid State Question 54 | Chemistry

A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be :

$$2\sqrt 2 a$$

$$\sqrt 2 a$$

$${a \over {\sqrt 2 }}$$

JEE Main 2015 (Offline)

MCQ (Single Correct Answer)

-1

Out of Syllabus

Sodium metal crystallizes in a body centred cubic lattice with a unit cell edge of 4.29 Å . The radius of sodium atom is approximately :

5.72 Å

0.93 Å

1.86 Å

3.22 Å

JEE Main 2014 (Offline)

MCQ (Single Correct Answer)

-1

Out of Syllabus

CsCl crystallises in body centred cubic lattice. If ‘a’ is its edge length then which of the following expressions is correct?

$${r_{C{s^ + }}} + {r_{C{l^ - }}} = {{\sqrt 3 } \over 2}a$$

$${r_{C{s^ + }}} + {r_{C{l^ - }}} = {3 \over 2}a$$

$${r_{C{s^ + }}} + {r_{C{l^ - }}} = \sqrt 3 a$$

$${r_{C{s^ + }}} + {r_{C{l^ - }}} = 3a$$

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