JEE Main 2021 (Online) 18th March Evening Shift | Solid State Question 28 | Chemistry

In a binary compound, atoms of element A form a hcp structure and those of element M occupy 2/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is :

M₂A₃

M₄A₃

M₄A

MA₃

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MCQ (Single Correct Answer)

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Out of Syllabus

A crystal is made up of metal ions 'M₁' and 'M₂' and oxide ions. Oxide ions form a ccp lattice structure. The cation 'M₁' occupies 50% of octahedral voids and the cation 'M₂' occupies 12.5% of tetrahedral voids of oxide lattice. The oxidation numbers of 'M₁' and 'M₂' are, respectively :

+ 3, + 1

+ 4, + 2

+ 1, + 3

+ 2, + 4

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MCQ (Single Correct Answer)

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Out of Syllabus

An element crystallises in a face-centred cubic (fcc) unit cell with cell edge $$a$$. The distance between the centres of two nearest octahedral voids in the crystal lattice is :

$$a$$

$${a \over 2}$$

$${a \over {\sqrt 2 }}$$

$${\sqrt 2 a}$$

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