### JEE Mains Previous Years Questions with Solutions

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### JEE Main 2015 (Offline)

Two coaxial solenoids of different radius carry current $I$ in the same direction. $\overrightarrow {{F_1}}$ be the magnetic force on the inner solenoid due to the outer one and $\overrightarrow {{F_2}}$ be the magnetic force on the outer solenoid due to the inner one. Then :
A
$\overrightarrow {{F_1}}$ is radially in wards and $\overrightarrow {{F_2}} = 0$
B
$\overrightarrow {{F_1}}$ is radially outwards and $\overrightarrow {{F_2}} = 0$
C
$\overrightarrow {{F_1}} = \overrightarrow {{F_2}} = 0$
D
$\overrightarrow {{F_1}}$ is radially inwards and $\overrightarrow {{F_2}}$ is radially outards

## Explanation

$\mathop {F{}_1}\limits^ \to = \mathop {F{}_2}\limits^ \to = 0$

because of action and reaction pair
2

### JEE Main 2014 (Offline)

Match List - $1$ (Electromagnetic wave type ) with List - $2$ (Its association/application) and select the correct option from the choices given below the lists:
A
$1 - iv,\,\,2 - iii,\,\,3 - ii,\,\,4 - i$
B
$1 - i,\,\,2 - ii,\,\,3 - iv,\,\,4 - iii$
C
$1 - iii,\,\,2 - ii,\,\,3 - i,\,\,4 - iv$
D
$1 - i,\,\,2 - ii,\,\,3 - iii,\,\,4 - iv$

## Explanation

$\left( 1 \right)\,\,\,\,\,\,$ Infrared rays are used to treat muscular strain because these are heat rays.

$\left( 2 \right)\,\,\,\,\,\,$ Radio waves are used for broadcasting because these waves have very long wavelength runging from few centimeters to few hundred kilometers

$\left( 3 \right)\,\,\,\,\,\,$ $X$-rays are used to detect fracture of bones because they have high penetrating power but they can't penetrate through denser medium like bones.

$\left( 4 \right)\,\,\,\,\,\,$ Ultraviolet rays are absorbed by ozone of the atmosphere.
3

### JEE Main 2014 (Offline)

During the propagation of electromagnetic waves in a medium:
A
Electric energy density is double of the magnetic energy density.
B
Electric energy density is half of the magnetic energy density.
C
Electric energy density is equal to the magnetic energy density.
D
Both electric and magnetic energy of densities are zero.

## Explanation

${E_0} = C{B_0}$ and $C = {1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$

Electric energy density $= {1 \over 2}{\varepsilon _0}{E_0}^2 = {\mu _E}$

Magnetic energy density $= {1 \over 2}{{{B_0}^2} \over {{\mu _0}}} = {\mu _B}$

Thus, ${\mu _E} = {\mu _B}$

Energy is equally divided between electric and magnetic field
4

### JEE Main 2014 (Offline)

In the circuit shown here, the point $'C'$ is kept connected to point $'A'$ till the current flowing through the circuit becomes constant. Afterward, suddenly, point $'C'$ is disconnected from point $'A'$ and connected to point $'B'$ at time $t=0.$ Ratio of the voltage across resistance and the inductor at $t=L/R$ will be equal to :
A
${e \over {1 - e}}$
B
$1$
C
$-1$
D
${{1 - e} \over e}$

## Explanation

Applying kirchhoffs law of voltage in closed loop

$- {V_R} - {V_C} = 0 \Rightarrow {{{V_R}} \over {{V_C}}} = - 1$