JEE Main 2019 (Online) 12th January Evening Slot | Alternating Current and Electromagnetic Induction Question 162 | Physics

JEE Main 2019 (Online) 12th January Evening Slot

MCQ (Single Correct Answer)

-1

A 10 m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0 ms^–1, at right angles to the horizontal component of the earth's magnetic field of 0.3 $$ \times $$ 10^–4 Wb/m². The value of the induced emf in wire is :

0.3 $$ \times $$ 10^–3 V

2.5 $$ \times $$ 10^–3 V

1.5 $$ \times $$ 10^–3 V

1.1 $$ \times $$ 10^–3 V

JEE Main 2019 (Online) 12th January Evening Slot

MCQ (Single Correct Answer)

-1

A paramagnetic material has 10²⁸ atoms/m³. Its magnetic susceptibility at temperature 350 K is 2.8 $$ \times $$ 10^–4. Its susceptibility at 300 K is :

3.726 $$ \times $$ 10^–4

2.672 $$ \times $$ 10^–4

3.672 $$ \times $$ 10^–4

3.267 $$ \times $$ 10^$$-$$4

JEE Main 2019 (Online) 12th January Evening Slot

MCQ (Single Correct Answer)

-1

In the above circuit, C = $${{\sqrt 3 } \over 2}$$$$\mu $$F, R₂ = 20 $$\Omega $$, L = $${{\sqrt 3 } \over {10}}$$ H and R₁ = 10 $$\Omega $$. Current in L-R₁ path is I₁ and in C-R₂ path it is I₂ . The voltage of A.C. source is given by, V = 200 $${\sqrt 2 }$$ sin (100 t) volts . The phase difference between I₁ and I₂ is :

JEE Main 2019 (Online) 12th January Evening Slot Physics - Alternating Current and Electromagnetic Induction Question 163 English

JEE Main 2019 (Online) 12th January Evening Slot Physics - Alternating Current and Electromagnetic Induction Question 163 English

150^o

90^o

30^o

0^o

JEE Main 2019 (Online) 11th January Evening Slot

MCQ (Single Correct Answer)

-1

A 27 mW laser beam has a cross-sectional area of 10 mm². The magnitude of the maximum electric field in this electromagnetic wave is given by :
[Given permittivity of space $$ \in $$₀ = 9 $$ \times $$ 10^–12 SI units, Speed of light c = 3 $$ \times $$ 10⁸ m/s]

2 kV/m

1 kV/m

1.4 kV/m

0.7 kV/m

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