JEE Main 2023 (Online) 29th January Evening Shift | Electromagnetic Induction Question 35 | Physics

JEE Main 2023 (Online) 29th January Evening Shift

MCQ (Single Correct Answer)

-1

A square loop of area 25 cm$$^2$$ has a resistance of 10 $$\Omega$$. The loop is placed in uniform magnetic field of magnitude 40.0 T. The plane of loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in 1.0 sec, will be

$$\mathrm{1.0\times10^{-3}~J}$$

$$\mathrm{5\times10^{-3}~J}$$

$$\mathrm{2.5\times10^{-3}~J}$$

$$\mathrm{1.0\times10^{-4}~J}$$

JEE Main 2023 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

Find the mutual inductance in the arrangement, when a small circular loop of wire of radius '$$R$$' is placed inside a large square loop of wire of side $$L$$ $$(L \gg R)$$. The loops are coplanar and their centres coincide :

JEE Main 2023 (Online) 29th January Morning Shift Physics - Electromagnetic Induction Question 36 English

$$M=\frac{\sqrt{2} \mu_{0} R}{L^{2}}$$

$$M=\frac{2 \sqrt{2} \mu_{0} R}{L^{2}}$$

$$M=\frac{2 \sqrt{2} \mu_{0} R^{2}}{L}$$

$$M=\frac{\sqrt{2} \mu_{0} R^{2}}{L}$$

JEE Main 2023 (Online) 25th January Evening Shift

MCQ (Single Correct Answer)

-1

A wire of length 1m moving with velocity 8 m/s at right angles to a magnetic field of 2T. The magnitude of induced emf, between the ends of wire will be __________.

20 V

8 V

16 V

12 V

JEE Main 2023 (Online) 24th January Evening Shift

MCQ (Single Correct Answer)

-1

A metallic rod of length 'L' is rotated with an angular speed of '$$\omega$$' normal to a uniform magnetic field 'B' about an axis passing through one end of rod as shown in figure. The induced emf will be :

JEE Main 2023 (Online) 24th January Evening Shift Physics - Electromagnetic Induction Question 33 English

$$\mathrm{\frac{1}{2}B^2L^2\omega}$$

$$\mathrm{\frac{1}{2}BL^2\omega}$$

$$\mathrm{\frac{1}{4}BL^2\omega}$$

$$\mathrm{\frac{1}{4}B^2L\omega}$$

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