1
JEE Main 2022 (Online) 28th July Evening Shift
+4
-1

White phosphorus reacts with thionyl chloride to give

A
$$\mathrm{PCl}_{5}, \mathrm{SO}_{2}$$ and $$\mathrm{S}_{2} \mathrm{Cl}_{2}$$
B
$$\mathrm{PCl}_{3}, \mathrm{SO}_{2}$$ and $$\mathrm{S}_{2} \mathrm{Cl}_{2}$$
C
$$\mathrm{PCl}_{3}, \mathrm{SO}_{2}$$ and $$\mathrm{Cl}_{2}$$
D
$$\mathrm{PCl}_{5}, \mathrm{SO}_{2}$$ and $$\mathrm{Cl}_{2}$$
2
JEE Main 2022 (Online) 28th July Evening Shift
+4
-1

Dinitrogen and dioxygen, the main constituents of air do not react with each other in atmosphere to form oxides of nitrogen because

A
$$\mathrm{N}_{2}$$ is unreactive in the condition of atmosphere.
B
Oxides of nitrogen are unstable.
C
Reaction between them can occur in the presence of a catalyst.
D
The reaction is endothermic and require very high temperature.
3
JEE Main 2022 (Online) 28th July Morning Shift
+4
-1

Match List - I with List - II, match the gas evolved during each reaction.

List - I List - II
(A) $$\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow}$$ (I) $$\mathrm{H}_{2}$$
(B) $$\mathrm{KMnO}_{4}+\mathrm{HCl} \rightarrow$$ (II) $$\mathrm{N}_{2}$$
(C) $$\mathrm{Al}+\mathrm{NaOH}+\mathrm{H}_{2} \mathrm{O} \rightarrow$$ (III) $$\mathrm{O}_{2}$$
(D) $$\mathrm{NaNO}_{3} \stackrel{\Delta}{\longrightarrow}$$ (IV) $$\mathrm{Cl}_{2}$$

Choose the correct answer from the options given below :

A
$$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})$$
B
$$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$$
C
$$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$$
D
$$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$$
4
JEE Main 2022 (Online) 27th July Evening Shift
+4
-1

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : Boron is unable to form $$\mathrm{BF}_{6}^{3-}$$.

Reason (R) : Size of B is very small.

In the light of the above statements, choose the correct answer from the options given below :

A
Both (A) and (R) are true and (R) is the correct explanation of (A)
B
Both (A) and (R) are true but (R) is not the correct explanation of (A)
C
(A) is true but (R) is false
D
(A) is false but (R) is true
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