In finding out refractive index of glass slab the following observations were made through travelling microscope 50 vernier scale division $$=49 \mathrm{~MSD} ; 20$$ divisions on main scale in each $$\mathrm{cm}$$
For mark on paper
$$\text { MSR }=8.45 \mathrm{~cm}, \mathrm{VC}=26$$
For mark on paper seen through slab
$$\mathrm{MSR}=7.12 \mathrm{~cm}, \mathrm{VC}=41$$
For powder particle on the top surface of the glass slab
$$\text { MSR }=4.05 \mathrm{~cm}, \mathrm{VC}=1$$
(MSR $$=$$ Main Scale Reading, VC = Vernier Coincidence)
Refractive index of the glass slab is :
To find the spring constant $$(k)$$ of a spring experimentally, a student commits $$2 \%$$ positive error in the measurement of time and $$1 \%$$ negative error in measurement of mass. The percentage error in determining value of $$k$$ is :
Match List I with List II
LIST I | LIST II | ||
---|---|---|---|
A. | Torque | I. | $$ \left[M^1 L^1 T^{-2} A^{-2}\right] $$ |
B. | Magnetic field | II. | $$ \left[L^2 A^1\right] $$ |
C. | Magnetic moment | III. | $$ \left[M^1 T^{-2} A^{-1}\right] $$ |
D. | Permeability of free space | IV. | $$ \left[M^1 L^2 T^{-2}\right] $$ |
Choose the correct answer from the options given below:
While measuring diameter of wire using screw gauge the following readings were noted. Main scale reading is $$1 \mathrm{~mm}$$ and circular scale reading is equal to 42 divisions. Pitch of screw gauge is $$1 \mathrm{~mm}$$ and it has 100 divisions on circular scale. The diameter of the wire is $$\frac{x}{50} \mathrm{~mm}$$. The value of $$x$$ is :