JEE Main 2020 (Online) 7th January Morning Slot | Redox Reactions Question 47 | Chemistry

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JEE Main 2020 (Online) 7th January Morning Slot

MCQ (Single Correct Answer)

-1

Oxidation number of potassium in K₂O. K₂O₂ and KO₂ respectively is :

+1, +2 and + 4

+1, +1 and + 1

+2, +1 and $$ + {1 \over 2}$$

+1, +4, and +2

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

An example of a disproportionation reaction is :

2NaBr + Cl₂ $$ \to $$ 2NaCl + Br₂

2KMnO₄ $$ \to $$ 2KMnO₄ + MnO₂ + O₂ (3) (4)

2CuBr $$ \to $$ CuBr₂ + Cu

2MnO₄ + 10I^– + 16H⁺ $$ \to $$ 2Mn₂⁺ + 5I₂ + 8H₂O

JEE Main 2019 (Online) 9th April Morning Slot

MCQ (Single Correct Answer)

-1

The correct order of the oxidation states of nitrogen in NO, N₂O, NO₂ and N₂O₃ is :

NO₂ < NO < N₂O₃ < N₂O

NO₂ < N₂O₃ < NO < N₂O

N₂O < NO < N₂O₃ < NO₂

N₂O < N₂O₃ < NO < NO₂

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

In order to oxidise a mixture of one mole of each of FeC₂O₄, Fe₂(C₂O₄)₃, FeSO₄ and Fe₂(SO₄)₃ in acidic medium, the number of moles of KMnO₄ required is :

1.5

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