JEE Main 2019 (Online) 12th January Morning Slot | Redox Reactions Question 51 | Chemistry

JEE Main 2019 (Online) 12th January Morning Slot

MCQ (Single Correct Answer)

-1

50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount of NaOH in 50 mL of the given sodium hydroxide solution is -

20 g

4 g

80 g

10 g

JEE Main 2019 (Online) 12th January Morning Slot

MCQ (Single Correct Answer)

-1

The hardness of a water sample (in terms of equivalents of CaCO₃) containing 10^–3 M CaSO₄ is (Molar mass of CaSO₄ = 136 g mol^–1)

90 ppm

100 ppm

50 ppm

10 ppm

JEE Main 2019 (Online) 10th January Evening Slot

MCQ (Single Correct Answer)

-1

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO₂ is :

JEE Main 2017 (Offline)

MCQ (Single Correct Answer)

-1

Which of the following reactions is an example of a redox reaction?

$$Xe{F_6}$$ + H₂O $$\to$$ $$XeO{F_4}$$ + 2HF

$$Xe{F_6}$$ + 2H₂O $$\to$$ $$XeO_2{F_2}$$ + 4HF

$$Xe{F_4}$$ + O₂F₂ $$\to$$ $$Xe{F_6}$$ + O₂

$$Xe{F_2}$$ + PF₅ $$\to$$ $${\left[ {XeF} \right]^ + }PF_6^ - $$

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