### JEE Mains Previous Years Questions with Solutions

4.5
star star star star star
1

### AIEEE 2005

One conducting $U$ tube can slide inside another as shown in figure, maintaining electrical contacts between the tubes. The magnetic field $B$ is perpendicular to the plane of the figure. If each tube moves towards the other at a constant speed $v,$ then the $emf$ induced in the circuit in terms of $B,l$ and $v$ where $l$ is the width of each tube, will be
A
$-Blv$
B
$blv$
C
$2$ $Blv$
D
zero

## Explanation

Relative velocity $= v + v = 2v$

$\therefore$ $emf.$ $= B.l\left( {2v} \right)$
2

### AIEEE 2005

The phase difference between the alternating current and $emf$ is ${\pi \over 2}.$ Which of the following cannot be the constituent of the circuit?
A
$R,L$
B
$C$ alone
C
$L$ alone
D
$L, C$

## Explanation

The difference for $R$-$L$ circuit lies between $\left( {0,{\pi \over 2}} \right)$
3

### AIEEE 2005

A circuit has a resistance of $12$ $ohm$ and an impedance of $15$ $ohm$. The power factor of the circuit will be
A
$0.4$
B
$0.8$
C
$0.125$
D
$1.25$

## Explanation

Power factor $= \cos \phi = {R \over Z} = {{12} \over {15}} = {4 \over 5} = 0.8$
4

### AIEEE 2005

A coil of inductance $300$ $mH$ and resistance $2\,\Omega$ is connected to a source of voltage $2$ $V$. The current reaches half of its steady state value in
A
$0.1$ $s$
B
$0.05$ $s$
C
$0.3$ $s$
D
$0.15$ $s$

## Explanation

KEY CONCEPT : The charging of inductance given

by, $i = {i_0}\left( {1 - {e^{ - {{Rt} \over L}}}} \right)$

${{{i_0}} \over 2} = {i_0}\left( {1 - {e^{ - {{Rt} \over L}}}} \right) \Rightarrow {e^{ - {{Rt} \over L}}} = {1 \over 2}$

Taking log on both the sides,

$- {{Rt} \over L} = \log 1 - \log 2$

$\Rightarrow t = {L \over R}\log 2 = {{300 \times {{10}^{ - 3}}} \over 2} \times 0.69$

$\Rightarrow t - 0.1\,\sec .$