1
JEE Main 2021 (Online) 16th March Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Match List - I with List - II :

List - I
Name of oxo acid
List - II
Oxidation state of 'P'
(a) Hypophosphorous acid (i) +5
(b) Orthophosphoric acid (ii) +4
(c) Hypophosphoric acid (iii) +3
(d) Orthophosphorous acid (iv) +2
(v) +1


Choose the correct answer from the options given below :
A
(a) - (iv), (b) - (v), (c) - (ii), (d) - (iii)
B
(a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)
C
(a) - (v), (b) - (i), (c) - (ii), (d) - (iii)
D
(a) - (v), (b) - (iv), (c) - (ii), (d) - (iii)
2
JEE Main 2021 (Online) 26th February Evening Shift
MCQ (Single Correct Answer)
+4
-1
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A : In TlI3, isomorphous to CsI3, the metal is present in +1 oxidation state.

Reason R : Tl metal has fourteen f electrons in its electronic configuration.

In the light of the above statements, choose the most appropriate answer from the options given below :
A
A is correct but R is not correct
B
A is not correct but R is correct
C
Both A and R are correct but R is NOT the correct explanation of A
D
Both A and R are correct and R is the correct explanation of A
3
JEE Main 2021 (Online) 26th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Find A, B and C in the following reactions :

$$N{H_3} + A + C{O_2} \to {(N{H_4})_2}C{O_3}$$

$${(N{H_4})_2}C{O_3} + {H_2}O + B \to N{H_4}HC{O_3}$$

$$N{H_4}HC{O_3} + NaCl \to N{H_4}Cl + C$$
A
$$A - {O_2};B - C{O_2};C - N{a_2}C{O_3}$$
B
$$A - {H_2}O;B - {O_2};C - NaHC{O_3}$$
C
$$A - {H_2}O;B - {O_2};C - N{a_2}C{O_3}$$
D
$$A - {H_2}O;B - C{O_2};C - NaHC{O_3}$$
4
JEE Main 2021 (Online) 26th February Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
On treating a compound with warm dil. H2SO4, gas X is evolved which turns K2Cr2O7 paper acidified with dil. H2SO4 to a green compound Y. X and Y respectively are :
A
X = SO2, Y = Cr2O3
B
X = SO3, Y = Cr2(SO4)3
C
X = SO3, Y = Cr2O3
D
X = SO2, Y = Cr2(SO4)3
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