JEE Main 2023 (Online) 31st January Evening Shift | p-Block Elements Question 83 | Chemistry

Given below are two statements :

Statement I: Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green

Statement II: The green colour observed is due to the formation of copper(I) metaborate

In light of the above statements, choose the most appropriate answer from the options given below :

Both Statement I and Statement II are false

Both Statement I and Statement II are true

Statement I is false but Statement II is true

Statement I is true but Statement II is false

JEE Main 2023 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

Boric acid is solid, whereas $\mathrm{BF}_3$ is gas at room temperature because of :

Strong van der Waal's interaction in Boric acid

Strong covalent bond in $\mathrm{BF}_{3}$

Strong hydrogen bond in Boric acid

Strong ionic bond in Boric acid

JEE Main 2023 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

During the borax bead test with $$\mathrm{CuSO_4}$$, a blue green colour of the bead was observed in oxidising flame due to the formation of :

CuO

Cu(BO$$_2)_2$$

Cu$$_3$$B$$_2$$

JEE Main 2023 (Online) 29th January Morning Shift

MCQ (Single Correct Answer)

-1

Out of Syllabus

"A" obtained by Ostwald's method involving air oxidation of NH$$_3$$, upon further air oxidation produces "B", "B" on hydration forms an oxoacid of Nitrogen along with evolution of "A". The oxoacid also produces "A" and gives positive brown ring test.

Identify A and B, respectively :

$$\mathrm{N_2O_3,NO_2}$$

$$\mathrm{NO_2,N_2O_5}$$

$$\mathrm{NO_2,N_2O_4}$$

$$\mathrm{NO,NO_2}$$

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