JEE Main 2019 (Online) 12th April Morning Slot | Ray & Wave Optics Question 162 | Physics

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

The value of numerical aperature of the objective lens of a microscope is 1.25. If light of wavelength 5000 $$\mathop A\limits^o $$ is used, the minimum separation between two points, to be seen as distinct, will be :

0.12 $$\mu $$m

0.38 $$\mu $$m

0.24 $$\mu $$m

0.48 $$\mu $$m

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

In a double slit experiment, when a thin film of thickness t having refractive index $$\mu $$. is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is ($$\lambda $$ is the wavelength of the light used) :

$${\lambda \over {2\left( {\mu - 1} \right)}}$$

$${\lambda \over {\left( {2\mu - 1} \right)}}$$

$${{2\lambda } \over {\left( {\mu - 1} \right)}}$$

$${\lambda \over {\left( {\mu - 1} \right)}}$$

JEE Main 2019 (Online) 12th April Morning Slot

MCQ (Single Correct Answer)

-1

A concave mirror has radius of curvature of 40 cm. It is at the bottom of a glass that has water filled up to 5 cm (see figure). If a small particle is floating on the surface of water, its image as seen, from directly above the glass, is at a distance d from the surface of water. The value of d is dose to: (Refractive index of water = 1.33) JEE Main 2019 (Online) 12th April Morning Slot Physics - Ray & Wave Optics Question 162 English

JEE Main 2019 (Online) 12th April Morning Slot Physics - Ray & Wave Optics Question 162 English

11.7 cm

6.7 cm

13.4 cm

8.8 cm

JEE Main 2019 (Online) 10th April Evening Slot

MCQ (Single Correct Answer)

-1

In a Young's double slit experiment, the ratio of the slit's width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be :

25 : 9

4 : 1

$${\left( {\sqrt 3 + 1} \right)^4}:16$$

9 : 1

PREVIOUS NEXT