JEE Main 2025 (Online) 23rd January Morning Shift | Periodic Table & Periodicity Question 12 | Chemistry | JEE Main - ExamSIDE.com

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1

JEE Main 2025 (Online) 23rd January Morning Shift

MCQ (Single Correct Answer)

+4

-1

The element that does not belong to the same period of the remaining elements (modern periodic table) is:

A

Platinum

B

Osmium

C

Iridium

D

Palladium

2

JEE Main 2025 (Online) 22nd January Evening Shift

MCQ (Single Correct Answer)

+4

-1

Given below are two statements :

Statement (I) : An element in the extreme left of the periodic table forms acidic oxides.

Statement (II) : Acid is formed during the reaction between water and oxide of a reactive element present in the extreme right of the periodic table.

In the light of the above statements, choose the correct answer from the options given below :

A

Both Statement I and Statement II are false

B

Both Statement I and Statement II are true

C

Statement I is true but Statement II is false

D

Statement I is false but Statement II is true

3

JEE Main 2025 (Online) 22nd January Morning Shift

MCQ (Single Correct Answer)

+4

-1

Match List-I with List-II.

	List - I		List - II
(A)	$\mathrm{Al}^{3+}<\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{F}^{-}$	(I)	Ionisation Enthalpy
(B)	$\mathrm{B}<\mathrm{C}<\mathrm{O}<\mathrm{N}$	(II)	Metallic character
(C)	$\mathrm{B}<\mathrm{Al}<\mathrm{Mg}<\mathrm{K}$	(III)	Electronegativity
(D)	$\mathrm{Si}<\mathrm{P}<\mathrm{S}<\mathrm{Cl}$	(IV)	Ionic radii

Choose the correct answer from the options given below :

A

(A)-(IV), (B)-(I), (C)- (II), (D)-(III)

B

(A)-(III), (B)-(IV), (C)- (II), (D)-(I)

C

(A)-(II), (B)-(III), (C)- (IV), (D)-(I)

D

(A)-(IV), (B)-(I), (C)- (III), (D)-(II)

4

JEE Main 2025 (Online) 22nd January Morning Shift

MCQ (Single Correct Answer)

+4

-1

Which of the following electronegativity order is incorrect?

A

$\mathrm{S}<\mathrm{Cl}<\mathrm{O}<\mathrm{F}$

B

$\mathrm{Al}<\mathrm{Si}<\mathrm{C}<\mathrm{N}$

C

$\mathrm{Al}<\mathrm{Mg}<\mathrm{B}<\mathrm{N}$

D

$\mathrm{Mg}<\mathrm{Be}<\mathrm{B}<\mathrm{N}$

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