NaClO₃ is used, even in spacecrafts, to produce O₂. The daily consumption of pure O₂ by a person is 492L at 1 atm, 300K. How much amount of NaClO₃, in grams, is required to produce O₂ for the daily consumption of a person at 1 atm, 300 K?
NaClO₃(s) + Fe(s) $$ \to $$ O₂(g) + NaCl(s) + FeO(s)
R = 0.082 L atm mol^–1 K^–1