1
MCQ (Single Correct Answer)

JEE Main 2017 (Online) 8th April Morning Slot

In which of the following reactions, hydrogen peroxide acts as an oxidizing agent ?
A
HOCl + H2O2 $$ \to $$ H3O+ + Cl$$-$$ + O2
B
I2 + H2O2 + 2OH$$-$$ $$ \to $$ 2I$$-$$ + 2H2O + O2
C
2Mn$$O_4^ - $$ + 3H2O2 $$ \to $$ 2 MnO2 + 3O2 + 2H2O + 2OH$$-$$
D
PbS + 4H2O2 $$ \to $$ PbSO4 + 4H2O

Explanation



Since, H2O2 gains electron to convert into H2O. Hence, H2O2 acts as an oxidizing agent.
2
MCQ (Single Correct Answer)

JEE Main 2020 (Online) 7th January Evening Slot

The redox reaction among the following is :
A
reaction of H2SO4 with NaOH.
B
formation of ozone form atmosphere oxygen in the presence of sunlight.
C
combination of dinitrogen with dioxygen at 2000 K
D
reaction of [Co(H2O)6]Cl3 With AgNO3

Explanation

N2 + O2 $$ \to $$ 2NO

during the reaction, oxidation of nitrogen take place from 0 to 2 and reduction of oxygen take place from 0 to –2. It means this reaction is redox reaction.

3O2 $$ \to $$ 2O3 (Non - redox reaction)

2NaOH + H2SO4 $$ \to $$ Na2SO4 + 2H2O (neutralization reaction)

[Co(H2O)6]Cl3 + 3AgNO3 $$ \to $$ 3AgCl $$ \downarrow $$ + [Co(H2O)6](NO3)3

Reaction of [CO(H2O)6]Cl3 with AgNO3 is not redox reaction. It is a precipitation reaction.
3
MCQ (Single Correct Answer)

JEE Main 2020 (Online) 9th January Morning Slot

The compound that cannot act both as oxidising and reducing agent is :
A
H3PO4
B
H2SO3
C
H2O2
D
HNO2

Explanation

In H3PO4, P is present in +5 oxidation state and it can act as reducing agent only.
4
MCQ (Single Correct Answer)

JEE Main 2021 (Online) 25th February Morning Slot

Which of the following equation depicts the oxidizing nature of H2O2?
A
$$C{L_2} + {H_2}{O_2} \to 2HCl + {O_2}$$
B
$$KI{O_4} + {H_2}{O_2} \to KI{O_3} + {H_2}O + {O_2}$$
C
$$2{I^ - } + {H_2}{O_2} + 2{H^ + } \to {I_2} + 2{H_2}O$$
D
$${I_2} + {H_2}{O_2} + 2O{H^ - } \to 2{I^ - } + 2{H_2}O + {O_2}$$

Explanation

$$2{I^ - } + {H_2}{O_2} + 2{H^ + } \to {I_2} + 2{H_2}O$$

Oxygen reduces from –1 to –2.

So, its reduction will takes place. Hence it will behave as oxidising agent or it shows oxidising nature.

While in other option it change from (–1) to 0.

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