JEE Main 2019 (Online) 8th April Evening Slot | Magnetics Question 186 | Physics

JEE Main 2019 (Online) 8th April Evening Slot

MCQ (Single Correct Answer)

-1

Two very long, straight, and insulated wires are kept at 90° angle from each other in xy-plane as shown in the figure. These wires carry currents of equal magnitude I, whose directions are shown in the figure. The net magnetic field at point P will be : JEE Main 2019 (Online) 8th April Evening Slot Physics - Magnetics Question 188 English

JEE Main 2019 (Online) 8th April Evening Slot Physics - Magnetics Question 188 English

$${{ + {\mu _0}I} \over {\pi d}}\left( {\mathop z\limits^ \wedge } \right)$$

$$ - {{{\mu _0}I} \over {2\pi d}}\left( {\mathop x\limits^ \wedge + \mathop y\limits^ \wedge } \right)$$

Zero

$$ {{{\mu _0}I} \over {2\pi d}}\left( {\mathop x\limits^ \wedge + \mathop y\limits^ \wedge } \right)$$

JEE Main 2019 (Online) 8th April Evening Slot

MCQ (Single Correct Answer)

-1

The magnetic field of an electromagnetic wave is given by :-

$$\mathop B\limits^ \to = 1.6 \times {10^{ - 6}}\cos \left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( {2\mathop i\limits^ \wedge + \mathop j\limits^ \wedge } \right){{Wb} \over {{m^2}}}$$

The associated electric field will be :-

$$\mathop E\limits^ \to = 4.8 \times {10^2}\cos \left( {2 \times {{10}^7}z - 6 \times {{10}^{15}}t} \right)\left( -2{\mathop i\limits^ \wedge + \mathop {j}\limits^ \wedge } \right){V \over m}$$

$$\mathop E\limits^ \to = 4.8 \times {10^2}\cos \left( {2 \times {{10}^7}z - 6 \times {{10}^{15}}t} \right)\left( 2{\mathop i\limits^ \wedge + \mathop {j}\limits^ \wedge } \right){V \over m}$$

$$\mathop E\limits^ \to = 4.8 \times {10^2}\cos \left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( {\mathop i\limits^ \wedge - \mathop {2j}\limits^ \wedge } \right){V \over m}$$

$$\mathop E\limits^ \to = 4.8 \times {10^2}\cos \left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( -{\mathop i\limits^ \wedge + \mathop {2j}\limits^ \wedge } \right){V \over m}$$

JEE Main 2019 (Online) 8th April Evening Slot

MCQ (Single Correct Answer)

-1

Two magnetic dipoles X and Y are placed at a separation d, with their axes perpendicular to each other. The dipole moment of Y is twice that of X. A particle of charge q is passing, through their midpoint P, at angle q = 45° with the horizontal line, as shown in figure. What would be the magnitude of force on the particle at that instant ?
(d is much larger than the dimensions of the dipole) JEE Main 2019 (Online) 8th April Evening Slot Physics - Magnetics Question 186 English

JEE Main 2019 (Online) 8th April Evening Slot Physics - Magnetics Question 186 English

$$ \left( {{{{\mu _0}} \over {4\pi }}} \right){2M \over {{{\left( {d/2} \right)}^3}}} \times qv$$

$$ \left( {{{{\mu _0}} \over {4\pi }}} \right){M \over {{{\left( {d/2} \right)}^3}}} \times qv$$

$$\sqrt 2 \left( {{{{\mu _0}} \over {4\pi }}} \right){M \over {{{\left( {d/2} \right)}^3}}} \times qv$$

JEE Main 2019 (Online) 8th April Morning Slot

MCQ (Single Correct Answer)

-1

A circular coil having N turns and radius r carries a current I. It is held in the XZ plane in a magnetic field B$${\mathop i\limits^ \wedge }$$ . The torque on the coil due to the magnetic field is :

$${{B{r^2}I} \over {\pi N}}$$

B$$\pi $$r²IN

Zero

$${{B\pi{r^2}I} \over { N}}$$

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