1
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
A magnetic dipole is acted upon by two magnetic fields which are inclined to each other at an angle of 75o. One of the fields has a magnitude of 15 mT. The dipole attains stable equilibrium at an angle of 30o with this field. The magnitude of the other field (in mT ) is close to
A
11
B
36
C
1
D
1060
2
JEE Main 2016 (Online) 9th April Morning Slot
+4
-1
To know the resistance G of a galvanometer by half deflection method, a battery of emf VE and resistance R is used to deflect the galvanometer by angle $$\theta$$. If a shunt of resistance S is needed to get half deflection then G, R and S are related by the equation :
A
2S (R + G) = RG
B
S (R + G) = RG
C
2S = G
D
2G = S
3
JEE Main 2016 (Offline)
+4
-1
Two identical wires $$A$$ and $$B,$$ each of length $$'l'$$, carry the same current $$I$$. Wire $$A$$ is bent into a circle of radius $$R$$ and wire $$B$$ is bent to form a square of side $$'a'$$. If $${B_A}$$ and $${B_B}$$ are the values of magnetic fields at the centres of the circle and square respectively, then the ratio $${{{B_A}} \over {{B_B}}}$$ is:
A
$${{{\pi ^2}} \over {16}}$$
B
$${{{\pi ^2}} \over {8\sqrt 2 }}$$
C
$${{{\pi ^2}} \over {8}}$$
D
$${{{\pi ^2}} \over {16\sqrt 2 }}$$
4
JEE Main 2015 (Offline)
+4
-1
Two long current carrying thin wires, both with current $$I,$$ are held by insulating threads of length $$L$$ and are in equilibrium as shown in the figure, with threads making an angle $$'\theta '$$ with the vertical. If wires have mass $$\lambda$$ per unit-length then the value of $$I$$ is :
($$g=$$ $$gravitational$$ $$acceleration$$ )

A
$$2\sqrt {{{\pi gL} \over {{\mu _0}}}\tan \theta }$$
B
$$\sqrt {{{\pi \lambda gL} \over {{\mu _0}}}\tan \theta }$$
C
$$\sin \theta \sqrt {{{\pi \lambda gL} \over {{\mu _0}\,\cos \theta }}}$$
D
$$2\sin \theta \sqrt {{{\pi \lambda gL} \over {{\mu _0}\,\cos \theta }}}$$
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