JEE Main 2024 (Online) 5th April Evening Shift | Magnetic Effect of Current Question 11 | Physics

JEE Main 2024 (Online) 5th April Evening Shift

MCQ (Single Correct Answer)

-1

The electrostatic force $$\left(\vec{F_1}\right)$$ and magnetic force $$\left(\vec{F}_2\right)$$ acting on a charge $$q$$ moving with velocity $$v$$ can be written :

$$\vec{F}_1=q \vec{B}, \vec{F}_2=q(\vec{B} \times \vec{v})$$

$$\vec{F}_1=q \vec{V} \cdot \vec{E}, \vec{F}_2=q(\vec{B} \cdot \vec{V})$$

$$\vec{F}_1=q \vec{E}, \vec{F}_2=q(\vec{V} \times \vec{B})$$

$$\vec{F}_1=q \vec{E}, \vec{F}_2=q(\vec{B} \times \vec{V})$$

JEE Main 2024 (Online) 5th April Morning Shift

MCQ (Single Correct Answer)

-1

In a co-axial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero :

inside the outer conductor

outside the cable

in between the two conductors

inside the inner conductor

JEE Main 2024 (Online) 4th April Morning Shift

MCQ (Single Correct Answer)

-1

An electron is projected with uniform velocity along the axis inside a current carrying long solenoid. Then :

the electron will experience a force at $$45^{\circ}$$ to the axis and execute a helical path.

the electron will be accelerated along the axis.

the electron path will be circular about the axis.

the electron will continue to move with uniform velocity along the axis of the solenoid.

JEE Main 2024 (Online) 31st January Evening Shift

MCQ (Single Correct Answer)

-1

A uniform magnetic field of $$2 \times 10^{-3} \mathrm{~T}$$ acts along positive $$Y$$-direction. A rectangular loop of sides $$20 \mathrm{~cm}$$ and $$10 \mathrm{~cm}$$ with current of $$5 \mathrm{~A}$$ is in $$Y-Z$$ plane. The current is in anticlockwise sense with reference to negative $$X$$ axis. Magnitude and direction of the torque is:

$$2 \times 10^{-4} \mathrm{~N}$$- $$\mathrm{m}$$ along negative $$Z$$-direction

$$2 \times 10^{-4} \mathrm{~N}$$ - $$\mathrm{m}$$ along positive $$X$$-direction

$$2 \times 10^{-4} \mathrm{~N}$$ - $$\mathrm{m}$$ along positive $$Y$$-direction

$$2 \times 10^{-4} \mathrm{~N}$$ - $$\mathrm{m}$$ along positive $$Z$$-direction

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