1
AIEEE 2009
MCQ (Single Correct Answer)
+4
-1
A current loop $$ABCD$$ is held fixed on the plane of the paper as shown in the figure. The arcs $$BC$$ (radius $$= b$$) and $$DA$$ (radius $$=a$$) of the loop are joined by two straight wires $$AB$$ and $$CD$$. A steady current $$I$$ is flowing in the loop. Angle made by $$AB$$ and $$CD$$ at the origin $$O$$ is $${30^ \circ }.$$ Another straight thin wire steady current $${I_1}$$ flowing out of the plane of the paper is kept at the origin. AIEEE 2009 Physics - Magnetic Effect of Current Question 172 English

Due to the presence of the current $${I_1}$$ at the origin:

A
The forces on $$AD$$ are $$BC$$ are zero.
B
The magnitude of the net force on the loop is given by $${{{I_1}I} \over {4\pi }}{\mu _0}\left[ {2\left( {b - a} \right) + {\raise0.5ex\hbox{$\scriptstyle \pi $} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 3$}}\left( {a + b} \right)} \right].$$
C
The magnitude of the net force on the loop is given by $${{{\mu _0}I{I_1}} \over {24ab}}\left( {b - a} \right).$$
D
The forces on $$AB$$ and $$DC$$ are zero.
2
AIEEE 2008
MCQ (Single Correct Answer)
+4
-1
A horizontal overhead powerline is at height of $$4m$$ from the ground and carries a current of $$100A$$ from east to west. The magnetic field directly below it on the ground is
$$\left( {{\mu _0} = 4\pi \times {{10}^{ - 7}}\,\,Tm\,\,{A^{ - 1}}} \right)$$
A
$$2.5 \times {10^{ - 7}}\,T$$ southward
B
$$5 \times {10^{ - 6}}\,T$$ northward
C
$$5 \times {10^{ - 6}}\,T$$ southward
D
$$2.5 \times {10^{ - 7}}\,T$$ northward
3
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
A charged particle with charge $$q$$ enters a region of constant, uniform and mutually orthogonal fields $$\overrightarrow E $$ and $$\overrightarrow B $$ with a velocity $$\overrightarrow v $$ perpendicular to both $$\overrightarrow E $$ and $$\overrightarrow B, $$ and comes out without any change in magnitude or direction of $$\overrightarrow v $$. Then
A
$$\overrightarrow v = \overrightarrow B \times \overrightarrow E /{E^2}$$
B
$$\overrightarrow v = \overrightarrow E \times \overrightarrow B /{B^2}$$
C
$$\overrightarrow v = \overrightarrow B \times \overrightarrow E /{B^2}$$
D
$$\overrightarrow v = \overrightarrow E \times \overrightarrow B /{E^2}$$
4
AIEEE 2007
MCQ (Single Correct Answer)
+4
-1
A charged particle moves through a magnetic field perpendicular to its direction. Then
A
Kinetic energy changes but the momentum is constant
B
the momentum changes but the kinetic energy is constant
C
both momentum and kinetic energy of the particle are not constant
D
both momentum and kinetic energy of the particle are constant
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