1
JEE Main 2024 (Online) 6th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An element $$\Delta l=\Delta x\hat{i}$$ is placed at the origin and carries a large current $$I=10 \mathrm{~A}$$. The magnetic field on the $$y$$-axis at a distance of $$0.5 \mathrm{~m}$$ from the elements $$\Delta x$$ of $$1 \mathrm{~cm}$$ length is:

JEE Main 2024 (Online) 6th April Morning Shift Physics - Magnetic Effect of Current Question 23 English

A
$$10 \times 10^{-8} \mathrm{~T}$$
B
$$8 \times 10^{-8} \mathrm{~T}$$
C
$$4 \times 10^{-8} \mathrm{~T}$$
D
$$12 \times 10^{-8} \mathrm{~T}$$
2
JEE Main 2024 (Online) 5th April Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

The electrostatic force $$\left(\vec{F_1}\right)$$ and magnetic force $$\left(\vec{F}_2\right)$$ acting on a charge $$q$$ moving with velocity $$v$$ can be written :

A
$$\vec{F}_1=q \vec{B}, \vec{F}_2=q(\vec{B} \times \vec{v})$$
B
$$\vec{F}_1=q \vec{V} \cdot \vec{E}, \vec{F}_2=q(\vec{B} \cdot \vec{V})$$
C
$$\vec{F}_1=q \vec{E}, \vec{F}_2=q(\vec{V} \times \vec{B})$$
D
$$\vec{F}_1=q \vec{E}, \vec{F}_2=q(\vec{B} \times \vec{V})$$
3
JEE Main 2024 (Online) 5th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
In a co-axial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero :
A
inside the outer conductor
B
outside the cable
C
in between the two conductors
D
inside the inner conductor
4
JEE Main 2024 (Online) 4th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

An electron is projected with uniform velocity along the axis inside a current carrying long solenoid. Then :

A
the electron will experience a force at $$45^{\circ}$$ to the axis and execute a helical path.
B
the electron will be accelerated along the axis.
C
the electron path will be circular about the axis.
D
the electron will continue to move with uniform velocity along the axis of the solenoid.
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