JEE Main 2019 (Online) 9th January Morning Slot | Magnetics Question 207 | Physics

JEE Main 2019 (Online) 9th January Morning Slot

MCQ (Single Correct Answer)

-1

A current loop, having two circular arcs joined by two radial lines is shown in the figure. It carries a current of 10 A. The magnetic field at point O will be close to :

JEE Main 2019 (Online) 9th January Morning Slot Physics - Magnetics Question 211 English

JEE Main 2019 (Online) 9th January Morning Slot Physics - Magnetics Question 211 English

1.0 $$ \times $$ 10^$$-$$7 T

1.5 $$ \times $$ 10^$$-$$7 T

1.5 $$ \times $$ 10^$$-$$5 T

1.0 $$ \times $$ 10^$$-$$5 T

JEE Main 2019 (Online) 9th January Morning Slot

MCQ (Single Correct Answer)

-1

A conducting circular loop made of a thin wire, has area 3.5 $$ \times $$ 10^$$-$$3 m² and resistance 10 $$\Omega $$. It is placed perpendicular to a time dependent magnetic field B(t) = (0.4T)sin(50$$\pi $$t). The field is uniform in space. Then the net charge flowing through the loop during t = 0 s and t = 10 ms is close to :

0.14 mC

0.7 mC

0.21 mC

0.6 mC

JEE Main 2019 (Online) 9th January Morning Slot

MCQ (Single Correct Answer)

-1

An infinitely long current carrying wire and a small current carrying loop are in the plane of the paper as shown. The radius of the loop is a and distance of its centre from the wire is d (d > > a). If the loop a applies a force F on the wire then :

JEE Main 2019 (Online) 9th January Morning Slot Physics - Magnetics Question 209 English

JEE Main 2019 (Online) 9th January Morning Slot Physics - Magnetics Question 209 English

$$F = 0$$

$$F \propto \left( {{a \over d}} \right)$$

$$F \propto \left( {{{{a^2}} \over {{d^3}}}} \right)$$

$$F \propto {\left( {{a \over d}} \right)^2}$$

JEE Main 2019 (Online) 9th January Morning Slot

MCQ (Single Correct Answer)

-1

A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point in space and time, $$\overrightarrow E = 63\widehat j\,V/m.$$ The corresponding magnetic field $$\overrightarrow {B,} $$ at that point will be :

18.9 $$ \times $$ 10^$$-$$8 $$\widehat k$$T

2.1 $$ \times $$ 10^$$-$$8 $$\widehat k$$T

6.3 $$ \times $$ 10^$$-$$8 $$\widehat k$$T

18.9 $$ \times $$ 10⁸ $$\widehat k$$T

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