JEE Main 2025 (Online) 29th January Morning Shift | Motion in a Plane Question 2 | Physics

Two projectiles are fired with same initial speed from same point on ground at angles of $(45^\circ - \alpha)$ and $(45^\circ + \alpha)$, respectively, with the horizontal direction. The ratio of their maximum heights attained is :

$ \frac{1+\sin\alpha}{1-\sin\alpha} $

$ \frac{1+\sin2\alpha}{1-\sin2\alpha} $

$ \frac{1-\tan\alpha}{1+\tan\alpha} $

$ \frac{1-\sin2\alpha}{1+\sin2\alpha} $

JEE Main 2024 (Online) 8th April Evening Shift

MCQ (Single Correct Answer)

-1

The angle of projection for a projectile to have same horizontal range and maximum height is :

$$\tan ^{-1}\left(\frac{1}{2}\right)$$

$$\tan ^{-1}(2)$$

$$\tan ^{-1}\left(\frac{1}{4}\right)$$

$$\tan ^{-1}(4)$$

JEE Main 2024 (Online) 4th April Morning Shift

MCQ (Single Correct Answer)

-1

The co-ordinates of a particle moving in $$x$$-$$y$$ plane are given by : $$x=2+4 \mathrm{t}, y=3 \mathrm{t}+8 \mathrm{t}^2$$.

The motion of the particle is :

uniform motion along a straight line.

non-uniformly accelerated.

uniformly accelerated having motion along a straight line.

uniformly accelerated having motion along a parabolic path.

JEE Main 2024 (Online) 30th January Evening Shift

MCQ (Single Correct Answer)

-1

Projectiles A and B are thrown at angles of $$45^{\circ}$$ and $$60^{\circ}$$ with vertical respectively from top of a $$400 \mathrm{~m}$$ high tower. If their ranges and times of flight are same, the ratio of their speeds of projection $$v_A: v_B$$ is :

[Take $$g=10 \mathrm{~ms}^{-2}$$]

$$1: 2$$

$$\sqrt{2}: 1$$

$$1: \sqrt{2}$$

$$1: \sqrt{3}$$

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Questions Asked from Motion in a Plane (MCQ (Single Correct Answer))

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