JEE Main 2013 (Offline) | Motion in a Plane Question 65 | Physics

A projectile is given an initial velocity of $$\left( {\widehat i + 2\widehat j} \right)$$ m/s, where $${\widehat i}$$ is along the ground and $${\widehat j}$$ is along the vertical. If g = 10 m/s², the equation of its trajectory is:

y = x - 5x²

y = 2x - 5x²

4y = 2x - 5x²

4y = 2x - 25x²

AIEEE 2012

MCQ (Single Correct Answer)

-1

A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be

$$20\sqrt 2 $$ m

10 m

$$10\sqrt 2 $$ m

20 m

AIEEE 2011

MCQ (Single Correct Answer)

-1

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v, the total area around the fountain that gets wet is :

$$\pi {{{v^4}} \over {{g^2}}}$$

$${\pi \over 2}{{{v^4}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over g}$$

AIEEE 2010

MCQ (Single Correct Answer)

-1

A particle is moving with velocity $$\overrightarrow v = k\left( {y\widehat i + x\widehat j} \right)$$, where K is a constant. The general equation for its path is

y = x² + constant

y² = x + constant

xy = constant

y² = x² + constant

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