JEE Main 2013 (Offline) | Motion Question 158 | Physics

A projectile is given an initial velocity of $$\left( {\widehat i + 2\widehat j} \right)$$ m/s, where $${\widehat i}$$ is along the ground and $${\widehat j}$$ is along the vertical. If g = 10 m/s², the equation of its trajectory is:

y = x - 5x²

y = 2x - 5x²

4y = 2x - 5x²

4y = 2x - 25x²

AIEEE 2012

MCQ (Single Correct Answer)

-1

A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be

$$20\sqrt 2 $$ m

10 m

$$10\sqrt 2 $$ m

20 m

AIEEE 2011

MCQ (Single Correct Answer)

-1

An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by :
$${{dv} \over {dt}} = - 2.5\sqrt v $$ where v is the instantaneous speed. The time taken by the object, to come to rest, would be :

2 s

4 s

8 s

1 s

AIEEE 2011

MCQ (Single Correct Answer)

-1

A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v, the total area around the fountain that gets wet is :

$$\pi {{{v^4}} \over {{g^2}}}$$

$${\pi \over 2}{{{v^4}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over {{g^2}}}$$

$$\pi {{{v^2}} \over g}$$

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